The wire loop in Fig. 30-22ais subjected, in turn, to six uniform magnetic fields, each directed parallel to the axis, which is directed out of the plane of the figure. Figure 30- 22bgives the z components Bz of the fields versus time . (Plots 1 and 3 are parallel; so are plots 4 and 6. Plots 2 and 5 are parallel to the time axis.) Rank the six plots according to the emf induced in the loop, greatest clockwise emf first, greatest counter-clockwise emf last.

Short Answer

Expert verified

The rank of six plots according to the emf induced in the loop is plot 1 and 3 ties, plot 2 and 5 ties, and plot 4 and 6 ties.

Step by step solution

01

Step 1: Given

The wire loop is subjected to six uniform magnetic fields, parallel to Z, directed out of the page.

02

Determining the concept

The direction of the induced emf is the same as that of the induced current. The direction of the induced current is such that its magnetic field opposes the change in the applied magnetic field.

Formulae are as follows:

ε=-dϕdt,

ϕ=B.A,

where,

ε= Induced emf,

ϕ= change in magnetic flux,

B = magnetic field,

A = surface area.

03

Determining the rank of six plots according to the emf induced in the loop

According to Faraday’s law, the induced emf depends upon the changing magnetic flux. i.e.

ε=-dϕdt,

The magnitude of the flux is determined by the magnetic field.

ϕ=B.A,

Thus, the magnitude of the emf depends upon the changing applied to the magnetic field.

ε=-dϕdt=-AdBdt,

In the case of plots 1 and 3, the plot has a positive slope. So, the magnetic field is increasing with time and is directed out of the page. Thus, the induced magnetic field will be opposite to it i.e. it will be directed into the page. Using the right-hand rule, the direction of the induced current will be clockwise. The direction of the emf is the same as that of the induced current hence, it will also be clockwise. The magnitude of the emf will be the same for both, since the magnitude of the flux change is the same.

In the case of plots 2 and 4, the magnetic field remains constant with time. Hence, no change inthe flux occurs. Thus, the induced emf will be zero for these plots.

In the case of plots 4 and 6, the plots have negative slopes. Thus, the magnetic field is decreasing with time. Thus, the induced field will try to oppose the decrease. Thus, the direction of the induced field will be the same as that of the applied field. So, it will be directed out of the page. Thus, the right-hand rule says, the direction of the induced current will be counter-clockwise. This is the same direction for the induced emf. The magnitude of the emf will be the same for both, since the magnitude of the flux change is the same.

Hence,the rank of six plots according to the emf induced in the loop is plot 1 and 3 ties, plot 2 and 5 ties, and plot 4 and 6 ties.

The magnitude of theinduced emf is given by Faraday’s law while Lenz’s law helps determine its direction. Thus,the magnitude and the direction of the induced emf using the information given by the plots can be determined.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: At a certain place, Earth’s magnetic field has magnitudeB=0.590gaussand is inclined downward at an angle of 70.0°to the horizontal. A flat horizontal circular coil of wire with a radius of 10.0 cmhas 1000 turnsand a total resistance of85.0Ω. It is connected in series to a meter with140Ωresistance. The coil is flipped through a half-revolution about a diameter, so that it is again horizontal. How much charge flows through the meter during the flip?

A coil with an inductance of 2.0H and a resistance of10Ωis suddenly connected to an ideal battery withε=100V. (a) What is the equilibrium current? (b) How much energy is stored in the magnetic field when this current exists in the coil?

Figure 30-29 shows three circuits with identical batteries, inductors, and resistors. Rank the circuits, greatest first, according to the current through the resistor labeled R (a) long after the switch is closed, (b) just after the switch is reopened a long time later, and (c) long after it is reopened

A coil is connected in series with a 10.0kresistor. An ideal 50.0 Vbattery is applied across the two devices, and the current reaches a value of 2.00 mAafter 5.00 ms.(a) Find the inductance of the coil. (b) How much energy is stored in the coil at this same moment?

In Figure,R=15Ω,L=5.0Hthe ideal battery has ε=10V, and the fuse in the upper branch is an ideal3.0 A fuse. It has zero resistance as long as the current through it remains less than3.0 A . If the current reaches3.0 A , the fuse “blows” and thereafter has infinite resistance. Switch S is closed at timet = 0 . (a) When does the fuse blow? (Hint: Equation 30-41 does not apply. Rethink Eq. 30-39.) (b) Sketch a graph of the current i through the inductor as a function of time. Mark the time at which the fuse blows.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free