In Figure,R=15Ω,L=5.0Hthe ideal battery has ε=10V, and the fuse in the upper branch is an ideal3.0 A fuse. It has zero resistance as long as the current through it remains less than3.0 A . If the current reaches3.0 A , the fuse “blows” and thereafter has infinite resistance. Switch S is closed at timet = 0 . (a) When does the fuse blow? (Hint: Equation 30-41 does not apply. Rethink Eq. 30-39.) (b) Sketch a graph of the current i through the inductor as a function of time. Mark the time at which the fuse blows.

Short Answer

Expert verified

a) Time at which the fuse blows is t = 1.5 s

b) The sketch of graph of the current through the inductor as a function of time and the time at which fuse blows is given below.

Step by step solution

01

Given

i) Resistance is R=15Ω

ii) Inductance is L=5.0H

iii) Battery emf is ε=10V

iv) Current through the fuse is i=3.0A

02

Understanding the concept

We use the concept of loop rule for the give circuit. Applying the loop rule, we can find the time at which the fuse blows. We can sketch the graph of the current through the inductor as a function of time.

Formulae:

For the given loop,

V=0

03

(a) Calculate the time at which the fuse blows.

Time at which the fuse blows:

We can apply the loop rule.

ε-Ldidt-iR=0ε=Ldidt+iR

Before the fuse blows, the current through the resistor is zero, so we can write

role="math" localid="1661427781225" ε=Ldidtdt=Lεdi

Integrating on both sides, we get

dt=Lεdit=Lεi

Plugging the values, we get

t=5.0103.0t=1.5s

04

(b) Sketch the graph of the current through the inductor as a function of time and mark the time at which the fuse blows:

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Most popular questions from this chapter

A long solenoid has a diameter of 12.0 cm.When a current i exists in its windings, a uniform magnetic field of magnitude B = 30.0 mTis produced in its interior. By decreasing i, the field is caused to decrease at the rate of 6.50mTs.(a) Calculate the magnitude of the induced electric field 2.20 cmfrom the axis of the solenoid.

(b) Calculate the magnitude of the induced electric field 8.20 cmfrom the axis of the solenoid.

In Fig. 30-63, R=4.0,L=8.0μHand the ideal battery hasε=20v. How long after switch S is closed is the current 2.0 mA?

In Fig. 30-26, a wire loop has been bent so that it has three segments: segment bc(a quarter-circle), ac(a square corner), and ab(straight). Here are three choices for a magnetic field through the loop:

(1)B1=3i^+7j^-5tk^,(2)B2=5ti^-4j^-15k^,(3)B3=2i^-5tj^-12k^,

where Bis in milliteslas and tis in seconds. Without written calculation, rank the choices according to (a) the work done per unit charge in setting up the induced current and (b) that induced current, greatest first. (c) For each choice, what is the direction of the induced current in the figure?

Question: At a certain place, Earth’s magnetic field has magnitudeB=0.590gaussand is inclined downward at an angle of 70.0°to the horizontal. A flat horizontal circular coil of wire with a radius of 10.0 cmhas 1000 turnsand a total resistance of85.0Ω. It is connected in series to a meter with140Ωresistance. The coil is flipped through a half-revolution about a diameter, so that it is again horizontal. How much charge flows through the meter during the flip?

:Inductors in parallel. Two inductors L1 and L2 are connected in parallel and separated by a large distance so that the magnetic field of one cannot affect the other. (a)Show that the equivalent inductance is given by

1Leq=1L2+1L2

(Hint: Review the derivations for resistors in parallel and capacitors in parallel. Which is similar here?) (b) What is the generalization of (a) for N inductors in parallel?

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