Figure 30-25 shows a circular region in which a decreasing uniform magnetic field is directed out of the page, as well as four concentric circular paths. Rank the paths according to the magnitude of E.dSevaluated along them, greatest first.

Short Answer

Expert verified

The rank of the paths according to the magnitude ofE.dS is:

d and c tie, b and then, a.

Step by step solution

01

Step 1: Given

The circular region has decreasing uniform magnetic field directed out of the page.

02

Determining the concept

The magnitude of the induced emf depends upon the magnitude of the changing magnetic flux through the area of the loop. The emf is related to the induced electric field in each part of the loop.

Formulae are as follows:

ε=E.dS,

Where,

ε= electric flux,

E = electric field,

dS = differential surface.

03

(a) Determining the rank of the paths according to the magnitude of  ε=∮E→.dS→

According to Faraday’s law, changing magnetic flux induces current and emf in the loop. The emf is related to the electric field produced in each part of the loop as,

ε=E.dS.

The loops c and d are outside the region having a magnetic field. So, even if the area enclosed is different, the net magnetic flux through both paths is the same. Hence, the induced emf will be the same for both paths.

Path b is having a larger radius than that of path a. Thus, the magnetic flux through the area of b s is more than that through the area of a. Hence, the emf induced for path b is more than a.

In other words, path a will be ranked last as the magnitude of the emf induced in the path is the least.

Hence,the rank of the paths according to the magnitude ofε=E.dS is: d and c tie, b and then, a.

The magnitude of the induced emf is decided by the magnitude of the changing magnetic flux through the area of the loop. Thus, the area of the loop decides the emf induced, and hence, the ranking of the path.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The inductance of a closely packed coil of 400 turnsis 8.0 mH. Calculate the magnetic flux through the coil when the current is 5.0 mA.

:Inductors in parallel. Two inductors L1 and L2 are connected in parallel and separated by a large distance so that the magnetic field of one cannot affect the other. (a)Show that the equivalent inductance is given by

1Leq=1L2+1L2

(Hint: Review the derivations for resistors in parallel and capacitors in parallel. Which is similar here?) (b) What is the generalization of (a) for N inductors in parallel?

Suppose the emf of the battery in the circuit shown in Figure varies with time t so that the current is given by i(t) = 3.0 +5.0 t , where i is in amperes and t is in seconds. Take R=4.0ΩandL=5.0H, and find an expression for the battery emf as a function of t. (Hint: Apply the loop rule.)

Question: In Figure, a stiff wire bent into a semicircle of radius a = 2.0cmis rotated at constant angular speed 40revsin a uniform 20mTmagnetic field. (a) What is the frequency? (b) What is the amplitude of the emf induced in the loop?

Question: In Figure, two straight conducting rails form a right angle. A conducting bar in contact with the rails starts at the vertex at time t = 0and moves with a constant velocity of 5.20m/salong them. A magnetic field with B = 0.350 Tis directed out of the page. (a) Calculate the flux through the triangle formed by the rails and bar atT = 3.00S. (b) Calculate the emf around the triangle at that time. (c) If the emf isε=atn, where a and n are constants, what is the value of n?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free