A toroidal inductor with an inductance of 9.0.mH encloses a volume of 0.0200m3. If the average energy density in the toroid is70.0J/m3, what is the current through the inductor?

Short Answer

Expert verified

5.58 A

Step by step solution

01

Given

i) Inductance of inductorL=90.0mH=90.0×10-3H

ii) Volume of toroidV=0.0200m3

ii) Average densityuB=70.0J/m3l

02

Understanding the concept

We use the formula of total energy stored for volumein the magnetic field into the formula of energy stored in the inductor’s magnetic field to find the current through the inductor.

Formula:

UB=12Li2UB=uBV

03

Calculate the current through the inductor

The magnetic field stored in the toroid is given by

UB=12Li2

Butthe total energy stored for volume V in the magnetic field is given by

UB=uBV

Therefore,

12Li2=uBVi=2uBVLi=270.0Jm30.0200m390.0×10-3Hi=5.58A

Therefore, the current through the inductor is 5.58 A.

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