What must be the magnitude of a uniform electric field if it is to have the same energy density as that possessed by a 0.50 T magnetic field?

Short Answer

Expert verified

1.5×108V/m

Step by step solution

01

Given

Magnetic fieldb=0.50T

02

Understanding the concept

We use the formula of energy density in the magnetic field and energy density in an electric field to find the magnitude of a uniform electric field if it is to have the same energy density as that possessed by amagnetic field.

Formula:

uE=12ε0E2uB=12B2u0

03

Calculate the magnitude of a uniform electric field required

The electric field density is given by

uE=12ε0E2

The magnetic field density is given by

uB=12B2u0

According to the given condition,

uE=uB12ε0E2=12B2u0E2=B2μ0ε0E=Bμ0ε0E=0.50T8.85×10-12F/m4π×10-7H/mE=1.5×108V/m

Therefore, the magnitude of a uniform electric field is 1.5×108V/m.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two coils connected as shown in Figure separately have inductances L1 and L2. Their mutual inductance is M. (a) Show that this combination can be replaced by a single coil of equivalent inductance given by

Leq=L1+L2+2M

(b) How could the coils in Figure be reconnected to yield an equivalent inductance of

Leq=L1+L2-2M

(This problem is an extension of Problem 47, but the requirement that the coils be far apart has been removed.)

How long would it take, following the removal of the battery, for the potential difference across the resistor in an RL circuit (with L = 2.00H, R = 3.00) to decay to 10.0% of its initial value?

A loop antenna of area2.00cm2and resistance 5.21 mis perpendicular to a uniform magnetic field of magnitude 17.0 mT. The field magnitude drops to zero in 2.96 ms. How much thermal energy is produced in the loop by the change in field?

Figure 30-24 shows two circuits in which a conducting bar is slid at the same speed vthrough the same uniform magnetic field and along a U-shaped wire. The parallel lengths of the wire are separated by 2Lin circuit 1 and by Lin circuit 2. The current induced in circuit 1 is counter clockwise. (a) Is the magnetic field into or out of the page? (b) Is the current induced in circuit 2 clockwise or counter clockwise? (c) Is the emf induced in circuit 1 larger than, smaller than, or the same as that in circuit 2?

Figure 30-30 gives the variation with time of the potential difference VRacross a resistor in three circuits wired as shown in Fig. 30-16. The circuits contain the same resistance Rand emf εbut differ in the inductance L . Rank the circuits according to the value of L, greatest first.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free