In Fig. 30-63, R=4.0,L=8.0μHand the ideal battery hasε=20v. How long after switch S is closed is the current 2.0 mA?

Short Answer

Expert verified

For 1.0×10-9safter switch S is closed, the value for the current is 2.0 mA

Step by step solution

01

Given

R=4.0=4.0×103ΩL=8.0μH=8.0×10-6Hε=20vI=2.0mA=2.0×10-3A

02

Understanding the concept

We have the equation for current in the loop. We rearrange the equation to find the required value.

Formula:

I=εR1-e-tτL

τL=LR

03

Calculate how long after switch S is closed is the current 2.0 mA

We have,

I=εR1-e-tτL

But,

τL=LRτL=8.0×10-64.0×103τL=2.0×10-9s2.0×103=204.0×103×1-e-t2.0×10-91-e-t2.0×10-9=2.0×10-3×4.0×103201-e-t2.0×10-9=0.4e-t2.0×10-9=0.4-1e-t2.0×10-9=-0.6e-t2.0×10-9=0.6

Taking natural log at both the sides, we get

-t2.0×10-9=In(0.6)t2.0×10-9=0.51t=2.0×10-9×0.51t=1.0×10-9s

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free