A coil with an inductance of 2.0H and a resistance of10Ωis suddenly connected to an ideal battery withε=100V. (a) What is the equilibrium current? (b) How much energy is stored in the magnetic field when this current exists in the coil?

Short Answer

Expert verified
  1. The equilibrium current is i0=10A
  2. The amount of energy is stored in the magnetic field when the current exists in the coil UB=100J

Step by step solution

01

Given

  1. The inductance of a coil is L = 2.0 H
  2. The resistance of a coil is R=10Ω
  3. The emf of an ideal battery is ε=100V
02

Understanding the concept

We need to use the equation of Ohm’s law to calculate the equilibrium current and the equation of energy stored in the magnetic field of an inductor.

Formulae:

i0=ERUB=12Li02

03

(a) Calculate the equilibrium current

According to Ohm’s law, the equilibrium current through the coil is

i0=εRi0=100V10Ωi0=10A

04

(b) Calculate the amount of energy is stored in the magnetic field when the current exists in the coil

The expression for the magnetic energy is

UB=12Li02UB=12×2.0H×(10A)2 UB=100J

Amount of energy stored in the magnetic field is 100J

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