How long would it take, following the removal of the battery, for the potential difference across the resistor in an RL circuit (with L = 2.00H, R = 3.00) to decay to 10.0% of its initial value?

Short Answer

Expert verified

The time required for the current to decay to 10% of its initial value is t = 1.54s

Step by step solution

01

Given

L=2.00HR=3.00i=0.1i0

02

Understanding the concept

When the source of constant emf is removed, the current decay from a valueaccording to the equation of decay of current given by 30.45. So we can use that equation to find the time.

Formula:

i=i0e-t/τLτL=LR

03

Calculate the time required for the current to decay to 10% of its initial value.

We have, the equation of decay of current as,

i=i0e-tτLii0=e-tτLi0i=etτL

Taking logofboththe sides

lni0i=lne-tτLlni0i=tτL

Where τL=LRandi=0.1i0

lnlni00.1i0=tRLt=LRlnln(10)t=2.003.00lnln(10)t=1.54s

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Figure (a) shows a circuit consisting of an ideal battery with emf ε=6.00mV, a resistance R, and a small wire loop of area 500cm2. For the time interval t = 10 s to t = 20 s, an external magnetic field is set up throughout the loop. The field is uniform, its direction is into the page in Figure (a), and the field magnitude is given by B = at, where B is in Tesla, a is a constant, and t is in seconds. Figure (b) gives the current i in the circuit before, during, and after the external field is set up. The vertical axis scale is set byis=2.0mA. Find the constant a in the equation for the field magnitude.

Question: In Figure, a stiff wire bent into a semicircle of radius a = 2.0cmis rotated at constant angular speed 40revsin a uniform 20mTmagnetic field. (a) What is the frequency? (b) What is the amplitude of the emf induced in the loop?

In Figure, after switch S is closed at timet=0, the emf of the source is automatically adjusted to maintain a constant current i through S. (a) Find the current through the inductor as a function of time. (b) At what time is the current through the resistor equal to the current through the inductor?

Two coils connected as shown in Figure separately have inductances L1 and L2. Their mutual inductance is M. (a) Show that this combination can be replaced by a single coil of equivalent inductance given by

Leq=L1+L2+2M

(b) How could the coils in Figure be reconnected to yield an equivalent inductance of

Leq=L1+L2-2M

(This problem is an extension of Problem 47, but the requirement that the coils be far apart has been removed.)

The figure shows two parallel loops of wire having a common axis. The smaller loop (radius r) is above the larger loop (radius R) by a distancex>>R. Consequently, the magnetic field due to the counterclockwise current i in the larger loop is nearly uniform throughout the smaller loop. Suppose that x is increasing at the constant ratedxdt=v. (a)Find an expression for the magnetic flux through the area of the smaller loop as a function of x. (b)In the smaller loop, find an expression for the induced emf. (c)Find the direction of the induced current.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free