The flux linkage through a certain coil of R=0.75Ωresistance would be ϕB=26mWbif there were a current ofin it. (a) Calculate the inductance of i=5.5Athe coil. (b) If a 6.0Videal battery were suddenly connected across the coil, how long would it take for the current to rise from 0 to 2.5 A?

Short Answer

Expert verified
  1. The inductance of the coil is L =4.7×10-3H
  2. If a 6.0 V ideal battery were suddenly connected across the coil, how long would it take for the current to rise from 0 to 2.5 A ist=2.3×10-3s

Step by step solution

01

Given

R=0.75ΩϕB=26mWb=26×10-3Wbi=5.5A

02

Understanding the concept

An inductor is a device that can be used to produce a magnetic field in aspecified region. If a current iis established through each of the N windings of an inductor, a magneticfluxϕBlinks those windings. The inductance Lof the inductor is given by equations 30-28. After that using the equation 30-41 for finding the total time required for current rises from 0 to 2.5.

Formula

L=ΦBii=εR1-e-RtL

03

(a) Calculate the inductance of the coil.

By using the equation 30-28 to find the inductance in the coil is

L=ΦBiSo,L=(26×10-3)5.5L=4.7×10-3H

04

(b) If a 6.0 V ideal battery were suddenly connected across the coil, calculate how long would it take for the current to rise from 0 to 2.5 A

Ifa constantis introduced into a single loop circuitcontaining a resistance Rand an inductance L, the current rises to an equilibrium value ofε/R

So the rise of current is

i=εR1-e-RtL

Rearrange this equation to find the time

iεR=1-e-RtLe-RtL=1-iRε

Taking natural log of both side

-RtL=ln1-iRεt=-LRln1-iRε

By substituting the value

t=-4.7×10-30.75ln1-2.50.756.0t=-6.27×10-3ln(0.6875)t=2.3×10-3s

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Most popular questions from this chapter

The figure shows two parallel loops of wire having a common axis. The smaller loop (radius r) is above the larger loop (radius R) by a distancex>>R. Consequently, the magnetic field due to the counterclockwise current i in the larger loop is nearly uniform throughout the smaller loop. Suppose that x is increasing at the constant ratedxdt=v. (a)Find an expression for the magnetic flux through the area of the smaller loop as a function of x. (b)In the smaller loop, find an expression for the induced emf. (c)Find the direction of the induced current.

In Fig. 30-26, a wire loop has been bent so that it has three segments: segment bc(a quarter-circle), ac(a square corner), and ab(straight). Here are three choices for a magnetic field through the loop:

(1)B1→=3i^+7j^-5tk^,(2)B2→=5ti^-4j^-15k^,(3)B3→=2i^-5tj^-12k^,

where Bis in milliteslas and tis in seconds. Without written calculation, rank the choices according to (a) the work done per unit charge in setting up the induced current and (b) that induced current, greatest first. (c) For each choice, what is the direction of the induced current in the figure?

A small loop of area 6.8 mm2is placed inside a long solenoid that hasand carries a sinusoidally varying current i of amplitude1.28 A and angular frequency rad/s.The central axes of the loop and solenoid coincide. What is the amplitude of the emf induced in the loop?

Att=0, a battery is connected to a series arrangement of a resistor and an inductor. If the inductive time constant is 37.0 ms, at what time is the rate at which energy is dissipated in the resistor equal to the rate at which energy is stored in the inductor’s magnetic field?

What must be the magnitude of a uniform electric field if it is to have the same energy density as that possessed by a 0.50 T magnetic field?

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