The flux linkage through a certain coil of R=0.75Ωresistance would be ϕB=26mWbif there were a current ofin it. (a) Calculate the inductance of i=5.5Athe coil. (b) If a 6.0Videal battery were suddenly connected across the coil, how long would it take for the current to rise from 0 to 2.5 A?

Short Answer

Expert verified
  1. The inductance of the coil is L =4.7×10-3H
  2. If a 6.0 V ideal battery were suddenly connected across the coil, how long would it take for the current to rise from 0 to 2.5 A ist=2.3×10-3s

Step by step solution

01

Given

R=0.75ΩϕB=26mWb=26×10-3Wbi=5.5A

02

Understanding the concept

An inductor is a device that can be used to produce a magnetic field in aspecified region. If a current iis established through each of the N windings of an inductor, a magneticfluxϕBlinks those windings. The inductance Lof the inductor is given by equations 30-28. After that using the equation 30-41 for finding the total time required for current rises from 0 to 2.5.

Formula

L=ΦBii=εR1-e-RtL

03

(a) Calculate the inductance of the coil.

By using the equation 30-28 to find the inductance in the coil is

L=ΦBiSo,L=(26×10-3)5.5L=4.7×10-3H

04

(b) If a 6.0 V ideal battery were suddenly connected across the coil, calculate how long would it take for the current to rise from 0 to 2.5 A

Ifa constantis introduced into a single loop circuitcontaining a resistance Rand an inductance L, the current rises to an equilibrium value ofε/R

So the rise of current is

i=εR1-e-RtL

Rearrange this equation to find the time

iεR=1-e-RtLe-RtL=1-iRε

Taking natural log of both side

-RtL=ln1-iRεt=-LRln1-iRε

By substituting the value

t=-4.7×10-30.75ln1-2.50.756.0t=-6.27×10-3ln(0.6875)t=2.3×10-3s

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