In a phasor diagram for any point on the viewing screen for the two slit experiment in Fig 35-10, the resultant wave phasor rotates60.0°in 2.50×10-16s. What is the wavelength?

Short Answer

Expert verified

Thus, the wavelength of light is 450nm.

Step by step solution

01

According to the question.

It is given that

Δϕ=60°=π3rad

The figure according to the question is:

The phasors rotate with constant angular velocity

ω=ΔϕΔt=π3×2.5×10-16s=4.19×1015rad/s

02

The wavelength of light in medium. 

Since, light waves travelling in a medium (air) where the wave speed is approximately c, then kc=ω,wherek=2πλ, which leads to

λ=2πcω=2π×3×108m/s4.19×1015rad/s=4.498×10-7m=450nm

Hence, the wavelength of light is, 450nm.

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Most popular questions from this chapter

In a double-slit experiment, the fourth-order maximum for a wavelength of 450 nm occurs at an angle of θ=90°. (a) What range of wavelengths in the visible range (400 nm to 700 nm) are not present in the third-order maxima? To eliminate all visible light in the fourth-order maximum, (b) should the slit separation be increased or decreased and (c) what least change is needed?

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