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Chapter 35: Q102P (page 1080)

In a phasor diagram for any point on the viewing screen for the two slit experiment in Fig 35-10, the resultant wave phasor rotates60.0°in 2.50×10-16 s. What is the wavelength?

Short Answer

Expert verified

Thus, the wavelength of light is 450nm.

Step by step solution

01

According to the question.

It is given that

Δϕ=60°=π3rad

The figure according to the question is:

The phasors rotate with constant angular velocity

ω=ΔϕΔt=π3×2.5×10-16 s=4.19×1015 rad/s

02

The wavelength of light in medium. 

Since, light waves travelling in a medium (air) where the wave speed is approximately c, then kc=ω,wherek=2πλ, which leads to

λ=2πcω=2π×3×108m/s4.19×1015rad/s=4.498×10-7m=450nm

Hence, the wavelength of light is, 450nm.

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Most popular questions from this chapter

In a double-slit experiment, the distance between slits is5.0mm and the slits are 1.0m from the screen. Two interference patterns can be seen on the screen: one due to light of wavelength 480nm, and the other due to light of wavelength 600nm. What is the separation on the screen between the third-order (m=3) bright fringes of the two interference patterns?

In Fig. 35-33, two light pulses are sent through layers of plastic with thicknesses of either Lor 2Las shown and indexes of refraction n1=1.55, n2=1.70, n3=1.60, n4=1.45,n5=1.59 , n6=1.65 and n7=1.50. (a) Which pulse travels through the plastic in less time? (b) What multiple of Lcgives the difference in the traversal times of the pulses?

Reflection by thin layers. In Fig. 35-42, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) The waves of rays r1and r2interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35- 2 refers to the indexes of refraction n1, n2andn3, the type of interference, the thin-layer thickness Lin nanometres, and the wavelength λin nanometres of the light as measured in air. Where λis missing, give the wavelength that is in the visible range. Where Lis missing, give the second least thickness or the third least thickness as indicated.

Suppose that Young’s experiment is performed with blue-green light of wavelength 500 nm. The slits are 1.20 mm apart, and the viewing screen is 5.40 m from the slits. How far apart are the bright fringes near the center of the interference pattern?

In Fig. 35-39, two isotropic point sources S1 and S2 emit light in phase at wavelength λ and at the same amplitude. The sources are separated by distance 2d=6λ. They lie on an axis that is parallel to an x axis, which runs along a viewing screen at distance D=20.0λ. The origin lies on the perpendicular bisector between the sources. The figure shows two rays reaching point P on the screen, at positionxP. (a) At what value of xPdo the rays have the minimum possible phase difference? (b) What multiple ofλ gives that minimum phase difference? (c) At what value ofxPdo the rays have the maximum possible phase difference? What multiple of λ gives (d) that maximum phase difference and (e) the phase difference when xP=6λ ? (f) When xP=6λ, is the resulting intensity at point P maximum, minimum, intermediate but closer to maximum, or intermediate but closer to minimum?
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