Figure 35-29 shows the transmission of light through a thin film in the air by a perpendicular beam (tilted in the figure for clarity). (a) Did rayr3undergo a phase shift due to reflection? (b) In wavelengths, what is the reflection phase shift for rayr4? (c) If the film thickness is L, what is the path length difference between raysr3andr4?

Short Answer

Expert verified

(a) There is no phase shift due to reflection in the rayr3.

(b) The reflection phase shift for a ray r4is 0.

(c) The path length difference between rays r3andr4is 2L.

Step by step solution

01

Given information 

The thickness of the thin film is, L

The two light rays passing through the thin film are, r3andr4.

02

Reflection shift 

When a light ray reflects from a medium with a higher value of refraction index, then a phase change of 180 degrees happens, and when it reflects from a medium with a smaller refraction index, no phase change happens.

If the light ray passes through a medium of thickness L without any reflection then its path length would also be equal to L.

03

Step 3(a): Reflection phase shift for ray 3 

From the diagram, it is clear that one incident ray gets refracted and passes through the thin film coming out of the other side of the film.

The path of the rayr3is the same as the incident ray, it means that there is no phase shift that happens due to the reflection in the rayr3.

Hence, there is no phase shift due to reflection in the rayrole="math" localid="1663144835974" r3.

04

Step 4(b): Reflection phase shift for ray 4 

The incident ray gets reflected two times inside the thin film and then passes out from the other side of the film.

If the direction of the refracted and reflected rayr4does not change, then its value of reflection phase shift would also be zero.

Hence, the reflection phase shift for a rayr4is 0.

05

Step 5(c): Path length difference between rays 3 and 4 

According to the question, the light beam istransmitted through a thin film in a perpendicular direction.

So, the formula for the path length difference between rays r3and r4 is given by,

Path length difference = Path length of r4- path length ofr3

Path length difference = (L+L+L)-L

Path length difference = 3L-L

Path length difference = 2L

Hence, the path length difference between raysr3androle="math" localid="1663144064356" r4is 2L.

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Most popular questions from this chapter

Figure 35-27a shows the cross-section of a vertical thin film whose width increases downward because gravitation causes slumping. Figure 35-27b is a face-on view of the film, showing four bright (red) interference fringes that result when the film is illuminated with a perpendicular beam of red light. Points in the cross section corresponding to the bright fringes are labeled. In terms of the wavelength of the light inside the film, what is the difference in film thickness between (a) points a and b and (b) points b and d?

The reflection of perpendicularly incident white light by a soap film in the air has an interference maximum at 600nmand a minimum at role="math" localid="1663024492960" 450nm, with no minimum in between. If n=1.33for the film, what is the film thickness, assumed uniform?

In Figure 35-50, two isotropic point sources S1and S2emit light in phase at wavelength λand at the same amplitude. The sources are separated by distance d=6.00λon an x axis. A viewing screen is at distance D=20.0λfrom S2and parallel to the y axis. The figure shows two rays reaching point P on the screen, at height yp. (a) At what value of do the rays have the minimum possible phase difference? (b) What multiple of λgives that minimum phase difference? (c) At what value of ypdo the rays have the maximum possible phase difference? What multiple of λgives (d) that maximum phase difference and (e) the phase difference when yp=d? (f) When yp=d, is the resulting intensity at point P maximum, minimum, intermediate but closer to maximum, or intermediate but closer to minimum?

Transmission through thin layers. In Fig. 35-43, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) Part of the light ends up in material 3 as ray r3(the light does not reflect inside material 2) and r4(the light reflects twice inside material 2). The waves of r3andr4interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-3 refers to the indexes of refraction n1,n2and n3the type of interference, the thin-layer thickness Lin nanometers, and the wavelength λin nanometers of the light as measured in air. Where λis missing, give the wavelength that is in the visible range. Where Lis missing, give the second least thickness or the third least thickness as indicated.

We wish to coat flat glass (n = 1.50) with a transparent material (n = 1.25) so that reflection of light at wavelength 600 nm is eliminated by interference. What minimum thickness can the coating have to do this?

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