Chapter 35: Q5P (page 1074)
How much faster, in meters per second, does light travel in sapphire than in diamond? See Table 33-1.
Short Answer
The difference in speed is .
Chapter 35: Q5P (page 1074)
How much faster, in meters per second, does light travel in sapphire than in diamond? See Table 33-1.
The difference in speed is .
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Get started for freeIn Fig. 35-4, assume that two waves of light in air, of wavelength , are initially in phase. One travels through a glass layer of index of refraction and thickness . The other travels through an equally thick plastic layer of index of refraction . (a) What is the smallest value should have if the waves are to end up with a phase difference of 5.65 rad? (b) If the waves arrive at some common point with the same amplitude, is their interference fully constructive, fully destructive, intermediate but closer to fully constructive, or intermediate but closer to fully destructive?
Transmission through thin layers. In Fig. 35-43, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) Part of the light ends up in material 3 as ray (the light does not reflect inside material 2) and (the light reflects twice inside material 2). The waves of and interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-3 refers to the indexes of refraction , the type.
Of interference, the thin-layer thickness in nanometres, and the wavelength in nanometres of the light as measured in air.
Where is missing, give the wavelength that is in the visible range.
Where is missing, give the second least thickness or the third least thickness as indicated?
In Fig. 35-45, a broad beam of monochromatic light is directed perpendicularly through two glass plates that are held together at one end to create a wedge of air between them. An observer intercepting light reflected from the wedge of air, which acts as a thin film, sees 4001 dark fringes along the length of the wedge. When the air between the plates is evacuated, only 4000 dark fringes are seen. Calculate to six significant figures the index of refraction of air from these data.
Reflection by thin layers. In Fig. 35-42, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) The waves of rays and interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35- 2 refers to the indexes of refraction , and, the type of interference, the thin-layer thickness in nanometres, and the wavelength in nanometres of the light as measured in air. Where is missing, give the wavelength that is in the visible range. Where is missing, give the second least thickness or the third least thickness as indicated.
A double-slit arrangement produces interference fringes for sodium light that have an angular separation of . For what wavelength would the angular separation be 10% greater?
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