Is there an interference maximum, a minimum, an intermediate state closer to a maximum, or an intermediate state closer to a minimum at point P in Fig. 35-10 if the path length difference of the two rays is

(a)2.2λ, (b)3.5λ, (c) 1.8λ, and (d) 1.0λ?

For each situation, give the value of associated with the maximum orminimum involved.

Short Answer

Expert verified

(a) There is an intermediate state at point P close to the maxima for m=2 when the path difference is2.2λ.

(b) There is a minimum at point P form=3when the path difference is3.5λ.

(c) There is an intermediate state at point P close to the maxima form=2when the path difference is1.8λ.

(d) There is a maxima at point P for m=1 when the path difference is 1.0λ.

Step by step solution

01

Given data:

Interference from a pair of slits.

02

Interference fringe path difference:

The path difference of two rays creating abright fringe of ordermfor slit separationlocalid="1663156893374" d ,screen distanceD and wavelength localid="1663156010374" λis

localid="1663156168036" L=mλ

path difference of two rays creating a dark fringe of order m for slit separationlocalid="1663156062331" D ,screen distance and wavelength λis

L=(m+12)λ .....(2)

03

(a) Determining fringe order for path difference 2.2λ 

From equation (1), path difference for the second order bright fringe is 2λand from equation (2) the path difference for the second order dark fringe is role="math" localid="1663156500745" 2+12λ=2.5λ.

Thus, the point for which the path difference is 2.2λ is an intermediate state closer to the second order maxima.

04

(b) Determining fringe order for path difference 3.5λ  :

From equation (2) the path difference for the third order dark fringe is,

3+12λ=3.5λ

Thus, the point for which the path difference is 3.5λ is the third order minima.

05

(c) Determining fringe order for path difference 1.8λ :

From equation (1), path difference for the second order bright fringe2λ is and from equation (2) the path difference for the first order dark fringe is,

1+12λ=1.5λ

Thus, the point for which the path difference is 1.8λ is an intermediate state closer to the second order maxima.

06

(d) Determining fringe order for path difference  1.0λ:

From equation (1) the path difference for the first order bright fringe is1λ .

Thus, the point for which the path difference is 1.0λ is the first order maxima.

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Most popular questions from this chapter

In Fig. 35-39, two isotropic point sources S1 and S2 emit light in phase at wavelength λ and at the same amplitude. The sources are separated by distance 2d=6λ. They lie on an axis that is parallel to an x axis, which runs along a viewing screen at distance D=20.0λ. The origin lies on the perpendicular bisector between the sources. The figure shows two rays reaching point P on the screen, at positionxP. (a) At what value of xPdo the rays have the minimum possible phase difference? (b) What multiple ofλ gives that minimum phase difference? (c) At what value ofxPdo the rays have the maximum possible phase difference? What multiple of λ gives (d) that maximum phase difference and (e) the phase difference when xP=6λ ? (f) When xP=6λ, is the resulting intensity at point P maximum, minimum, intermediate but closer to maximum, or intermediate but closer to minimum?

Reflection by thin layers. In Fig. 35-42, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) The waves of rays r1and r2interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35- 2 refers to the indexes of refraction n1, n2, and n3, the type of interference, the thin-layer thickness in nanometres, and the wavelength λ in nanometres of the light as measured in air. Where λis missing, give the wavelength that is in the visible range. Where Lis missing, give the second least thickness or the third least thickness as indicated.

In Fig. 35-37, two radio frequency point sources S1and S2, separated by distance d=2.0m, are radiating in phase with λ=0.50m. A detector moves in a large circular path around the two sources in a plane containing them. How many maxima does it detect?

Reflection by thin layers. In Fig. 35-42, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) The waves of rays r1and r2interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35- 2 refers to the indexes of refraction n1, n2and n3, the type of interference, the thin-layer thickness Lin nanometres, and the wavelength λin nanometres of the light as measured in air. Where λis missing, give the wavelength that is in the visible range. Where localid="1663142040666" Lis missing, give the second least thickness or the third least thickness as indicated

Figure 35-22 shows two light rays that are initially exactly in phase and that reflect from several glass surfaces. Neglect the slight slant in the path of the light inthe second arrangement.

(a) What is the path length difference of the rays?

In wavelengthsλ,

(b) what should that path length difference equal if the rays are to be exactly out of phase when they emerge, and

(c) what is the smallest value of that will allow that final phase difference?

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