Figure 35-24a gives intensity lversus position x on the viewing screen for the central portion of a two-slit interference pattern. The other parts of the figure give phasor diagrams for the electric field components of the waves arriving at the screen from the two slits (as in Fig. 35-13a).Which numbered points on the screen bestcorrespond to which phasor diagram?

(a) Figure 1

(b) Figure 2

(c) Figure 3

(d) Figure 4

Short Answer

Expert verified

a) The phase difference in Figure 2 corresponds to points 3 and 5 on Figure 1

b) The phase difference in Figure 3 corresponds to points 1 and 4 on Figure 1.

c) The phase difference in Figure 4 corresponds to point 2 on Figure 1

Step by step solution

01

Given data:

Phase differences between two waves for three different cases are provided in the given phasor diagrams

02

Relation between phase difference and the interference pattern:

The phase difference between interfering waves for the formation of maxima

ϕ=2nπn=0,1,2,3... .....(1)

Phase difference between interfering waves for the formation of minima

ϕ=(2n+1)πn=0,1,2,3... .....(2)

03

(a) Determining the interference point for the first phase difference:

The phase difference in the first figure 2 can be represented by

ϕ=2n+1π,n=0,1,2,3...

This represents minima in the interference pattern and thus can correspond to points 3 and 5 on figure 1.

04

(b) Determining the interference point for the second phase difference:

The phase difference in the first figure 2 can be represented by

ϕ=2nπn=0,1,2..

This represents maxima in the interference pattern and thus can correspond to points 1 and 4 in figure 1.

05

(c) Determining the interference point for the second phase difference:

The phase difference in the first figure 2 can be represented by

ϕ=nπ2,n=1,5,9...

This represents points between maxima and minima in the interference pattern and thus can correspond to point 2 on figure 1.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Transmission through thin layers. In Fig. 35-43, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) Part of the light ends up in material 3 as ray r3 (the light does not reflect inside material 2) and r4(the light reflects twice inside material 2). The waves of r3 and r4 interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-3 refers to the indexes of refraction n1,n2andn3, the type.

Of interference, the thin-layer thickness L in nanometres, and the wavelength λ in nanometres of the light as measured in air.

Where λ is missing, give the wavelength that is in the visible range.

Where Lis missing, give the second least thickness or the third least thickness as indicated?

In a double-slit experiment, the distance between slits is5.0mm and the slits are 1.0m from the screen. Two interference patterns can be seen on the screen: one due to light of wavelength 480nm, and the other due to light of wavelength 600nm. What is the separation on the screen between the third-order (m=3) bright fringes of the two interference patterns?

In Fig. 35-35, two light rays go through different paths by reflecting from the various flat surfaces shown.The light waves have a wavelength of 420.0 nm and are initially in phase. What are the (a) smallest and (b) second smallest value of distance L that will put the waves exactly out of phase as they emerge from the region?

In Fig. 35-45, a broad beam of monochromatic light is directed perpendicularly through two glass plates that are held together at one end to create a wedge of air between them. An observer intercepting light reflected from the wedge of air, which acts as a thin film, sees 4001 dark fringes along the length of the wedge. When the air between the plates is evacuated, only 4000 dark fringes are seen. Calculate to six significant figures the index of refraction of air from these data.

Monochromatic green light, of wavelength 500 nm, illuminates two parallel narrow slits 7.70 mm apart. Calculate the angular deviation ( θin Fig. 35-10) of the third-order (m=3)bright fringe (a) in radians and (b) in degrees.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free