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Chapter 35: Q7P (page 1074)

The speed of yellow Light (from a sodium lamp) in a certain liquid is measured to be1.92×108ms . What is the index of refraction of this liquid for the Light?

Short Answer

Expert verified

The index of refraction of the liquid is1.56

Step by step solution

01

Definition of Light

Light is an electromagnetic wave that, when it falls on an object, comes visible to the human eye, light transmits spatial and temporal information used in the optics field.

02

Determination of the index of refraction of the liquid

The formula for calculating the refractive index are:

n=cv

Here, c is the speed of Light in a vacuum, and v is the speed of Light in the given medium.

Therefore, the refractive index of the liquid is:

n=3×108ms1.92×108ms=1.56

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Most popular questions from this chapter

In Fig. 35-48, an airtight chamber of length d=5.0cm is placed in one of the arms of a Michelson interferometer. (The glass window on each end of the chamber has negligible thickness.) Light of wavelength l λ=500nm is used. Evacuating the air from the chamber causes a shift of 60 bright fringes. From these data and to six significant figures, find the index of refraction of air at atmospheric pressure.

Figure 35-46a shows a lens with radius of curvature lying on a flat glass plate and illuminated from above by light with wavelength l. Figure 35-46b (a photograph taken from above the lens) shows that circular interference fringes (known as Newton’s rings) appear, associated with the variable thickness d of the air film between the lens and the plate. Find the radii r of the interference maxima assumingr/R≤1.

A thin film with index of refraction n=1.40 is placed in one arm of a Michelson interferometer, perpendicular to the optical path. If this causes a shift of 7.0 bright fringes of the pattern produced by light of wavelength 589nm, what is the film thickness?

Find the slit separation of a double-slit arrangement that will produce interference fringes0.018 radapart on a distant screen when the light has wavelengthλ=589 nm.

In a double-slit experiment, the fourth-order maximum for a wavelength of 450 nm occurs at an angle of θ=90°. (a) What range of wavelengths in the visible range (400 nm to 700 nm) are not present in the third-order maxima? To eliminate all visible light in the fourth-order maximum, (b) should the slit separation be increased or decreased and (c) what least change is needed?
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