Figure 35-25 shows two sources s1 and s2 that emit radio waves of wavelengthλin all directions. The sources are exactly in phase and are separated by a distance equal to 1.5λ . The vertical broken line is the perpendicular bisector of the distance between the sources.

(a) If we start at the indicated start point and travel along path 1, does the interference produce a maximum all along the path, a minimum all along the path, or alternating maxima and minima? Repeat for

(b) path 2 (along an axis through the sources) and

(c) path 3 (along a perpendicular to that axis).

Short Answer

Expert verified

(a) The interference produces maxima all along path 1.

(b) The interference produces minima all along path 2.

(c) The interference produces alternating maxima and minima all along path 3.

Step by step solution

01

Given data

Distance between the two sources = 1.5λ

02

Interference fringe path difference

The path difference of two rays creating a bright fringe of order m for slit separation d, screen distance D, and wavelength λis

ΔL=mλ …(i)

The path difference of two rays creating a dark fringe of order m for slit separation d, screen distance D and wavelength λis

ΔL=(m+12)λ…(ii)

03

(a) Determining the path difference between light from the two sources in path 1

For any point y path 1, the path difference between light rays from the two sources is

ΔL=0.75λ2+y2-0.75λ2+y2=0

This is equal to equation (i) with m=0. Thus path 1 has bright fringes all along.

04

(b) Determining the path difference between light from the two sources in path 2

For any point on path 2 at a distance a from source 2, the path difference between light rays from the two sources is

ΔL=a+1.5λ-a=1.5λ

This is equal to equation (ii) with m=1. Thus path 1 has dark fringes all along.

05

(c) Determining the path difference between light from the two sources in path 3 

For any point on path 3 at a horizontal distance a from source 2 and vertical distance y, the path difference between light rays from the two sources is

ΔL=a+1.5λ2+y2-a2+y2

This function has a maximaΔL=1.5λat y=0 and tends to 0 asy. Thus there is a dark fringe at y=0, a bright fringe when ΔLreduces to 1λ, another dark fringe when ΔLreduces to 0.5λand finally a bright fringe as y. Thus there are alternating bright and dark fringes.

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Most popular questions from this chapter

In Fig. 35-40, two isotropic point sources of light (S1 and S2) are separated by distance 2.70μmalong a y axis and emit in phase at wavelength 900 nm and at the same amplitude. A light detector is located at point P at coordinate xPon the x axis. What is the greatest value of xP at which the detected light is minimum due to destructive interference?

In Fig. 35-35, two light rays go through different paths by reflecting from the various flat surfaces shown.The light waves have a wavelength of 420.0 nm and are initially in phase. What are the (a) smallest and (b) second smallest value of distance L that will put the waves exactly out of phase as they emerge from the region?

Transmission through thin layers. In Fig. 35-43, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) Part of the light ends up in material 3 as ray r3(the light does not reflect inside material 2) and r4(the light reflects twice inside material 2). The waves of r3andr4interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-3 refers to the indexes of refraction n1,n2and n3the type of interference, the thin-layer thickness Lin nanometers, and the wavelength λin nanometers of the light as measured in air. Where λis missing, give the wavelength that is in the visible range. Where Lis missing, give the second least thickness or the third least thickness as indicated.

Transmission through thin layers. In Fig. 35-43, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) Part of the light ends up in material 3 as ray r3(the light does not reflect inside material 2) and r4(the light reflects twice inside material 2). The waves of r3and r4interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-3 refers to the indexes of refraction n1,n2and n3, the type of interference, the thin-layer thickness L in nanometers, and the wavelength in nanometers of the light as measured in air. Where λis missing, give the wavelength that is in the visible range. Where Lis missing, give the second least thickness or the third least thickness as indicated.

Figure 35-24a gives intensity lversus position x on the viewing screen for the central portion of a two-slit interference pattern. The other parts of the figure give phasor diagrams for the electric field components of the waves arriving at the screen from the two slits (as in Fig. 35-13a).Which numbered points on the screen bestcorrespond to which phasor diagram?

(a) Figure 1

(b) Figure 2

(c) Figure 3

(d) Figure 4

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