In Fig 35-54, two isotropic point sources S1and S2emit light at wavelength λ=400nm. Source S1is located at y=640nm, source S2is located at y=-640nm. At point P1(at x=720nm), the wave from S2arrives ahead of the wave from S1by a phase difference of 0.600πrad. (a) What multiple of λgives the phase difference between the waves from the two sources as the waves from the two sources as the waves arrive at point P2, which is located at y=720nm? (The figure is not drawn to scale) (b) If the waves arrive at P2with equal amplitudes, is the interference there fully constructive, fully destructive, intermediate but closer to fully destructive, intermediate but closer to fully destructive?

Short Answer

Expert verified

Thus,

(a) the wavelength is 2.90λ.

(b) the nature is intermediate.

Step by step solution

01

Multiple of λ gives phase difference.

(a)

Since P1is equidistant from S1and S2conclude the sources are not in phase with each other. Their phase difference is ΔϕSource=0.60πrad, which may be expressed in terms of wavelengths as

ΔϕSource=0.60π2πλ=0.3λ

Now, S1is closer to P2than S2is source S1is 80nm from P2while sourceS2 is 1380 nm from P2. Here we find a difference of ΔϕPath=3.2λ. Thus, the net difference is:

ΔϕPath=Deltaϕpath-ΔϕSource=2.90λ

Hence, the wavelength is 2.90λ.

02

Wave is the interference.

(b)

A whole number would mean fully constructive so the result is of the following nature: intermediate, but close to fully constructive.

Hence, the nature is intermediate.

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Most popular questions from this chapter

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