Figure 35-57 shows an optical fiber in which a central platic core of index of refractionn1=1.58-is surrounded by a plastic sheath of index of refractionn2=1.53. Light can travel along different paths within the central core, leading to different travel times through the fiber, resulting in information loss. Consider light that travels directly along the central axis of the fiber and light that is repeatedly reflected at the critical angle along the core-sheath interface, reflecting from side to side as it travels down the central core. If the fiber length is 300 m, what is the difference in the travel times along these two routes?

Short Answer

Expert verified

Thus, the difference in the travel times along two routes is 51.6ns.

Step by step solution

01

Light travel along different paths within the central core.

A light ray travelling directly along the central axis reaches the end in time

tdirect=Lv1=n1Lc

For the ray taking the critical zig –zag path, only its velocity component along the core axis direction contributes to reach the other end of the fiber. That component isv1cosθ , so the time of travel for this ray is:

tzig-zag=1v1cosθ=n1Lc1-(sinθn1)2

Using results from the previous solution. Plugging in sinθ=n12-n22and simplifying gives:

tzig-zag=n1Lc(n2n1)=n12Lcn3

02

The difference in the travel times along two routes.

The difference is written as follows:

Δt=tzig-zag-tdirect=n1Lcn3-n1Lc=n1Lcn1n2-1

Withn1=1.58,n2=1.53andL=300mgives

Δt=n1Lcn1n2-1

=1.58800m3×108m/s1.581.53-1

=5.16×10-8s

=51.6ns

Hence, the difference in the travel times along two routes is 51.6ns.

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In Fig. 35-45, a broad beam of light of wavelength 683 nm is sent directly downward through the top plate of a pair of glass plates. The plates are 120 mm long, touch at the left end, and are separated by 48.0μm at the right end. The air between the plates acts as a thin film. How many bright fringes will be seen by an observer looking down through the top plate?

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