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Chapter 35: Q96P (page 1080)

A camera lens with index of refraction greater than 1.30 is coated with a thin transparent film of index of refraction 1.25 to eliminate by interference the reflection of light at wavelength λ that is incident perpendicularly on the lens. What multiple of λgives the minimum film thickness needed?

Short Answer

Expert verified

Thus, the minimum film needed is 0.200.

Step by step solution

01

The thin film interference of a coating on glass lens.

The formula for the thin film interference of coating on the glass lens:

Lmin=λ4n2

02

The minimum film thickness needed by multiple of .

Use the above formula as follows:

Lmin=λ4n2=λ41.25=0.200λ

Further solve as follows:

Lmin=0.200λLminλ=0.200

Hence, the minimum film needed is 0.200.

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