Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 7: 8P (page 171)

A ice block floating in a river is pushed through a displacement d→=(15m)i^-(12m)j^along a straight embankment by rushing water, which exerts a force data-custom-editor="chemistry" F→=(210N)i^-(150N)j^ on the block. How much work does the force do on the block during the displacement?

Short Answer

Expert verified

The work done on the block during the displacement is 5.0×103J.

Step by step solution

01

Given data

  1. Displacement, d→=15mi^-12mj^.
  2. Force, F→=210Ni^-150Nj^.
02

Understanding the concept

Using the formula ofthework done due to force over a distance, we can find the work done on the block during the displacement.

Formula:

W=F→.d→

03

Calculate the work done by the force on the block during the displacement

Work done can be calculated as,

W=F→.d→

Substitute the values in the above expression, and we get,

W=210Ni^-150Nj^.15mi^-12mj^W=3150+1800N.mW=4950N.mW=5.0×103J

Therefore, the work done on the block during the displacement is 5.0×103J.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A father racing his son has half the kinetic energy of the son, who has half the mass of the father. The father speeds up by 1.0m/sand then has the same kinetic energy as the son. What are the original speeds of (a) the father and (b) the son?

(a) at a certain instant, a particle-like object is acted on by a force F→=(4.0 N)i^-(2.0 N)j^+(9.0 N)k^ while the object’s velocity is v→=-(2.0 m/s)i^+(4.0 m/s)k^. What is the instantaneous rate at which the force does work on the object?

(b) At some other time, the velocity consists of only a y component. If the force is unchanged and the instantaneous power is -12W , what is the velocity of the object?

In Fig.7-34, a 0.250kgblock of cheese lies on the floor of a elevator cab that is being pulled upward by a cable through distance d1=2.40m and then through distance d2=10.5m. (a) Through , if the normal force on the block from the floor has constant magnitudeFN=3.00N , how much work is done on the cab by the force from the cable? (b) Through d2, if the work done on the cab by the (constant) force from the cable is 92.61kJ, what is the magnitude ofFN?

A 230 kg crate hangs from the end of a rope of length L= 12.0 m . You push horizontally on the crate with a varying force F⇀to move it distance d= 4.00 m to the side (Fig.7-44).(a) What is the magnitude of F⇀when the crate is in this final position? During the crate’s displacement, what are (b) the total work done on it, (c) the work done by the gravitational force on the crate, and (d) the work F⇀done by the pull on the crate from the rope? (e) Knowing that the crate is motionless before and after its displacement, use the answers to (b), (c), and (d) to find the work your force does on the crate. (f) Why is the work of your force not equal to the product of the horizontal displacement and the answer to (a)?

A force F→=(2.00i^+9.00j^+5.30k^)Nacts on a 2.90 kg object that moves in time interval 2.10 s from an initial position r→1=(2.7i^-2.90j^+5.50k^)mto a final position r→2=(-4.10i^+3.30j^+5.40k^)m. Find (a) the work done on the object by the force in that time interval, (b) the average power due to the force during that time interval, and (c) the angle between vectors r→1and r→2.
See all solutions

Recommended explanations on Physics Textbooks

Dynamics

Read Explanation

Nuclear Physics

Read Explanation

Thermodynamics

Read Explanation

Geometrical and Physical Optics

Read Explanation

Modern Physics

Read Explanation

Fundamentals of Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free