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Chapter 7: Q75P (page 176)

What is the power of the force required to move a4500kgelevator cab with a load of 1800 kgupward at constant speed 3.80 m/s?

Short Answer

Expert verified

The power of the force to move an 4500 kg elevator cab with a load of 1800 kg upward at a constant speed 3.80 m/s is 235 KW

Step by step solution

01

Given information

It is given that,

i) Mass of elevator cab 4500 kg

ii) Mass of load 1800 KG

iii) Speed v=3.80 m/s

02

Determining the concept

Using the formula of power in terms of force and velocity, find the power of force when it moves an object with a constant velocity.

Formula is as follow:

p=Fv

Where,

F is force, vis velocity and Pis the power.

03

Determining the power of the force

Now,

p=Fv

But,the total force is,

Ftotal=massofelevatorcab+massofload9.8m/s2Ftotal=4500kg+1800kg9.8m/s2Ftotal=61740N

Therefore,

P=61740N3.80msP=234612W=235kW

Therefore, thepower of the force to move an 4500kg elevator cab with a load of 1800 kg upward at a constant speed 3.80 m/s is 235kW

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Most popular questions from this chapter

A 5.0 kg block moves in a straight line on a horizontal frictionless surface under the influence of a force that varies with position as shown in Fig.7-39. The scale of the figure’s vertical axis is set byFs=10.0N. How much work is done by the force as the block moves from the origin to x=8.0cm?

At, t = 0 force F→=(-5.00i^+5.00j^+4.00k^)Nbegins to act on a 2.00 kg particle with an initial speed of 4.00 m / s . What is the particle’s speed when its displacement from the initial point is role="math" localid="1657949233150" d→=(2.00i^+2.00j^+7.00k^)m?

An initially stationary 2.0kgobject accelerates horizontally and uniformly to a speed of10 m/sin3.0 s. (a) In that 3.0 sinterval, how much work is done on the object by the force accelerating it? What is the instantaneous power due to that force (b) at the end of the interval and (c) at the end of the first half of the interval?

Is positive or negative work done by a constant force f→on a particle during a straight-line displacement d→if (a) the angle between f→andd→is30°; (b) the angle is 100°; (c) localid="1657168288688" f→=2i^-3j^and d→=-4i^?

Figure 7-27 shows an overhead view of three horizontal forces acting on a cargo canister that was initially stationary but now moves across a frictionless floor. The force magnitudes are F1=3.00N, F2=4.00N, and F3=10.00N, and the indicated angles are θ2=50.0°and θ3=35.0°. What is the net work done on the canister by the three forces during the first 4.00 m of displacement?
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