Figure shows a snapshot of a proton moving at velocityv=200msj^toward a long straight wire with current i=350mA. At the instant shown, the proton’s distance from the wire is d=2.89cm. In unit-vector notation, what is the magnetic force on the proton due to the current?

Short Answer

Expert verified

The magnitude of magnetic force on proton is -7.75×10-23Ni^.

Step by step solution

01

Given

  1. Permeability of free space, μ0=4π×10-7TmA.
  2. Given distance, d=2.89cm.
  3. Charge on proton, q=1.6×10-19.
  4. Velocity of particle, v=-200j^.
  5. Current carried by wire,i=350mA.
02

Determine the concept and the formulas:

Calculate the magnetic field due to the long wire at the position of proton. Use this value in the equation of magnetic force to calculate it.

Formula:

Magnetic field

B=μ0i2πr

Magnetic force, F=qv×B.

03

Calculate the magnitude of magnetic force on proton

First of all, we have to find the magnetic field B.

B=μ0i2πr

B=4π×10-7×.3502×3.14×2.89×10-2

B=2.42×10-6T

According to right hand rule, we can say that the magnetic field is out of paper inlocalid="1663227168373" +kdirection.

B=2.4221×10-6Tk^

Now, force is

F=qv×B

F=1.6×10-19-200j^×2.42×10-6k^

localid="1663227211827" F=-7.75×10-23Ni^

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