Chapter 28: Q 8P (page 829)
Question: An electric field ofand a perpendicular magnetic field of act on a moving electron to produce no net force. What is the electron’s speed?
Short Answer
The electron’s speed is .
Chapter 28: Q 8P (page 829)
Question: An electric field ofand a perpendicular magnetic field of act on a moving electron to produce no net force. What is the electron’s speed?
The electron’s speed is .
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Get started for freeAn electron is accelerated from rest through potential difference Vand then enters a region of uniform magnetic field, where itundergoes uniform circular motion. Figure 28-38 gives the radius rof thatmotion versus V1/2. The vertical axis scale is set byand the horizontal axis scale is set by What is the magnitude of the magnetic field?
An alpha particle can be produced in certain radioactive decays of nuclei and consists of two protons and two neutrons. The particle has a charge of and a mass of , where is the atomic mass unit, with kg. Suppose an alpha particle travels in a circular path of radius cm in a uniform magnetic field with . Calculate (a) its speed (b) its period of revolution, (c) its kinetic energy, and (d)the potential difference through which it would have to be accelerated to achieve this energy.
A wire lying along a yaxis from y=0to y=0.250mcarries a current of 2.00mAin the negative direction of the axis. The wire fully lies in a nonuniform magnetic field that is given by
In unit-vector notation, what is the magnetic force on the wire?
A positron with kinetic energykeV is projected into a uniform magnetic field of magnitude T, with its velocity vector making an angle of 89.0° with.
(a) Find the period.
(b) Find the pitch p.
(c) Find the radius rof its helical path.
Two concentric, circular wire loops, of radii r1 = 20.0cm and r2 = 30.0 cm, are located in an xyplane; each carries a clockwise current of 7.00 A (Figure).
(a) Find the magnitude of the net magnetic dipole moment of the system.
(b) Repeat for reversed current in the inner loop.
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