What uniform magnetic field, applied perpendicular to a beam of electrons moving at 1.30×106 m/s, is required to make the electrons travel in a circular arc of radius 0.350 m?

Short Answer

Expert verified

The required magnetic field is2.11×10-5T .

Step by step solution

01

Listing the given quantities

  • Velocity isV = .1.3×106 m/s
  • Radius is r =.0.350m
02

Understanding the concept of centripetal force and magnetic field

Weuse the equilibrium condition of the magnetic force on the electron and centripetal force due to the circular path.

Formula:

Fm=qvB

Fc=mv2r

03

 Step 3: Explanation

For the circular motion of an electron:

Fm=FcqvB=mv2rB=mvrq

Substituting the given values in the above expression, and we get,

B=9.11×10-31×1.3×1060.35×1.6×10-19=2.11×10-5T

The required magnetic field is2.11×10-5T .

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