Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 28: Q40P (page 831)

A wire 1.80 m long carries a current of13.0 A and makes an angle of 35.0°with a uniform magnetic field of magnitudeB=1.50 T. Calculate the magnetic force on the wire.

Short Answer

Expert verified

The magnetic force on the wire is 20.1N.

Step by step solution

01

Listing the given quantities

  • Current in the conductor,i=13.0A
  • Magnetic field,B=1.50T
  • Length of the conductor,L=1.80m
  • The angle between current and field, θ=35°
02

Understanding the concept of magnetic force

By using the formulas of magnetic force in terms of current and magnetic field and substituting the given quantities, we can find the magnitude of the magnetic force.

Formula:

Magnetic force, FB=iLBsinθ

03

Calculation of magnetic force on the wire

The magnetic force is given by:

FB=iLBsinθ

Where

i=Current,L=Lengthoftheconductor,B=Magneticfield,θ=Anglebetweencurrentandfield

Therefore,

role="math" localid="1662458941501" FB=13.01.801.50sin35°=20.1N

The magnetic force on the wire is 20.1N.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Figure 28-28 shows the path of an electron in a region of uniform magnetic field. The path consists oftwo straight sections, each between a pair of uniformly charged plates, and two half-circles. Which plate isat the higher electric potential in

(a) the top pair of plates and

(b) the bottom pair?

(c) What is the direction of the magnetic field?

Question: A proton travels through uniform magnetic and electric fields. The magnetic fieldis B→=-2.5i^mT.At one instant the velocity of the proton is v→=2000j^m/s At that instant and in unit-vector notation, what is the net force acting on the proton if the electric field is (a) role="math" localid="1663233256112" 4.00k^V/m, (b) -4.00k^V/mand (c)4.00i^V/m?

Atom 1 of mass 35uand atom 2 of mass 37u are both singly ionized with a charge of +e. After being introduced into a mass spectrometer (Fig. 28-12) and accelerated from rest through a potential difference V=7.3kV, each ion follows a circular path in a uniform magnetic field of magnitude B=0.50T. What is the distanceΔxbetween the points where the ions strike the detector?

Figure 28-29 shows 11 paths through a region of uniform magnetic field. One path is a straight line; the rest are half-circles. Table 28-4 gives the masses, charges, and speeds of 11 particles that take these paths through the field in the directions shown. Which path in the figure corresponds to which particle in the table? (The direction of the magnetic field can be determined by means of one of the paths, which is unique.)

Physicist S. A. Goudsmit devised a method for measuring the mass of heavy ions by timing their period of revolution in a known magnetic field. A singly charged ion of iodine makes 7revin a 45.0mTfield in 1.29ms. Calculate its mass in atomic mass units.
See all solutions

Recommended explanations on Physics Textbooks

Electricity

Read Explanation

Fields in Physics

Read Explanation

Conservation of Energy and Momentum

Read Explanation

Electrostatics

Read Explanation

Magnetism

Read Explanation

Solid State Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free