The magnetic dipole moment of Earth has magnitude8.00×1022J/T . Assume that this is produced by charges flowing in Earth’s molten outer core. If the radius of their circular path is 3500 km, calculate the current they produce.

Short Answer

Expert verified

i=2.08×109A

Step by step solution

01

Given

The radius of the earth=r=3500km=3500×103m

The magnetic dipole moment of the earth = μ=8.00×1022J/T

02

Understanding the concept

The charges flowing in the molten outer core of the earth produce the magnetic dipole moment. The current produced by the charges can be calculated by substituting the given quantities in the formula for magnetic dipole moment.

μ=NiA

03

Calculate the current produced

The magnetic dipole moment is calculated as

μ=NiA

Here,N=1andA=πr2

μ=iπ2

Rearranging the equation to find the value of the current.

i=μπr2i=8.00×10223.14×3500×1032i=2.08×109A

Hence, i=2.08×109A

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