: Assume the average value of the vertical component of Earth’s magnetic field is43μT (downward) for all of Arizona, which has an area of 2.95×105km2. (a)What is the magnitude and (b) What is the direction (inward or outward) of the net magnetic flux through the rest of Earth’s surface (the entire surface excluding Arizona)?

Short Answer

Expert verified

(a) The magnitude of net magnetic flux through the rest of the Earth’s surface isϕearth=1.3×107Wb.

(b) Its direction is outward

Step by step solution

01

Given

The magnetic field of Arizona,B=43μT

Area of Arizona, A=2.95×105km2

02

Determining the concept

Use the magnetic flux formula to find the net magnetic flux through the rest of the earth’s surface. The sign of the flux shows its direction. Magnetic flux is a measurement of the total magnetic field which passes through a given area. It is a useful tool for helping describe the effects of the magnetic force on something occupying a given area.

The formula is as follows:

ϕ=BA

where ϕis the flux,B is the magnetic field, and A is the area.

03

(a) Determining the magnitude of net magnetic flux through the rest of the Earth’s surface

The magnitude of net magnetic flux through the rest of the Earth’s surface:

Take the negative sign for downward magnetic field and positive sign for the upward magnetic field.

The magnetic flux through Arizona is,

ϕB=-BA

ϕB=-43×10-6T2.95×105km2103mkm2

ϕB=-1.3×107Wb

The negative sign shows that this flux goes inward.

Since

role="math" localid="1663146065927" ϕnet=0ϕearth+ϕarizona=0ϕearth=-ϕarizonaϕearth=--1.3×107Wbϕearth=1.3×107Wb

This is the flux that goes through the rest of the earth’s surface.

Therefore, the magnitude of net magnetic flux through the rest of the Earth’s surface is 1.3×107Wb.

04

(b) Determining the direction (inward or outward) of the net magnetic flux through the rest of Earth’s surface (the entire surface excluding Arizona)

The positive sign of the earth’s flux shows that its direction is outward.

Hence, its direction is outward.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The magnitude of the magnetic dipole moment of Earth is 8.0×1022J/T. (a) If the origin of this magnetism were a magnetized iron sphere at the center of Earth, what would be its radius? (b) What fraction of the volume of Earth would such a sphere occupy? Assume complete alignment of the dipoles. The density of Earth’s inner core isrole="math" localid="1662967671929" 14g/cm3 .The magnetic dipole moment of an iron atom is 2.1×10-23J/T. (Note:Earth’s inner core is in fact thought to be in both liquid and solid forms and partly iron, but a permanent magnet as the source of Earth’s magnetism has been ruled out by several considerations. For one, the temperature is certainly above the Curie point.)

If an electron in an atom has an orbital angular momentum withm=0, what are the components (a) Lorb,zand (b)μorb,z? If the atom is in an external magnetic fieldBthat has magnitude35mTand is directed along the z axis, what are (c) the energyUorbassociated withμorband(d) the energyUspinassociated withμs? (e) If, instead, the electron hasm=-3, what are (e)Lorb,z? (f) μorb,z(g) Uorband (h)Uspin?

Figure 32-24 shows three loop models of an electron orbiting counterclockwise within a magnetic field. The fields are non-uniform for models 1 and 2 and uniform for model 3. For each model, are (a) the magnetic dipole moment of the loop and (b) the magnetic force on the loop directed up, directed down, or zero?

A parallel-plate capacitor with circular plates of radius 0.10mis being discharged. A circular loop of radius0.20mis concentric with the capacitor and halfway between the plates. The displacement current through the loop is2.0A. At what rate is the electric field between the plates changing?

What is the energy difference between parallel and antiparallel alignment of the zcomponent of an electron’s spin magnetic dipole moment with an external magnetic field of magnitude0.25 T, directed parallel to the zaxis?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free