A magnet in the form of a cylindrical rod has a length of 5.00cmand a diameter of1.00cm. It has a uniform magnetization of5.30×103A/m. What is its magnetic dipole moment?

Short Answer

Expert verified

The magnetic dipole moment is 2.08×10-2J/T.

Step by step solution

01

Listing the given quantities 

Length of cylinder,l=5.0×10-2m

Diameter of cylinder,2r=1.0×10-2m

Magnetization,M=5.3×103A/m

02

Understanding the concepts of magnetization

We know that magnetic moment per unit volume is magnetization. We can find the magnetic dipole moment by substituting the given values in the formula for magnetization.

Formula:

μ=Mπr2l

03

 Step 3: Calculations of the magnetic dipole moment

Magnetization is given by

M=μV

Where,Vis the volume and μis the magnetic dipole moment

The volume of the cylinder is given byV=πr2l

Therefore,

M=μV=μπr2l

Rearranging the above equation, we get,

μ=Mπr2l=(5.3×103)×π×(0.5)2×104×5.0×102=2.08×10-2J/T

The magnetic dipole moment is 2.08×10-2J/T.

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