6.2×1014HzAn atom (not a hydrogen atom) absorbs a photon whose associated frequency is . By what amount does the energy of the atom increase?

Short Answer

Expert verified

The energy of the atom is increased by 4.12×10-19J.

Step by step solution

01

The energy of the photon:

The expression of the energy of the photon is given by,

E=hf ….. (1)

Here, h is plank constant, and f is frequency of the photon.

02

Define the amount of increase in the energy of the atom:

Substitute 6.626×10-34J.sfor h, and 6.2×1014Hzfor f in equation (1).

E=6.626×10-34J.s6.2×1014Hz=4.12×10-19J

Hence, the energy of the atom is increased by 4.12×10-19J.

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