What must be the width of a one-dimensional infinite potential well if an electron trapped in it in the n=3 state is to have an energy of 4.7 eV ?

Short Answer

Expert verified

0.85 nm

Step by step solution

01

Given data

En=4.7eVn=3

02

Energy in a potential well

The nth state energy of a particle of mass m in an infinite potential well of width L is

En=n2h28mL2........1

03

Determining the width of the potential well

Here h is the Planck's constant having value

h=6.626×10-34J.sandc=2.998×108m/s,hc=6.626×10-34J.s2.998×108m/s1.602×10-19J/eV10-9m/nm=1240eV.nm

Using the mc2value for an electron from Table 37-3 511×103eV, Eq.39 – 4 can be rewritten as

En=n2h28mL2=n2hc28mc2L2

For n=3,

L=nhc8mc2En=31240eV.nm8511×103eV4.7eV=0.85nm

Thus, the width is 0.85nm.

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