Chapter 2: Q110P (page 39)

Question: On average, an eye blink lasts about 100 ms. How far does a MiG - 25“Foxbat” fighter travel during a pilot’s blink if the plane’s average velocity is3400 km/hr?

Expert verified

The distance traveled by the fighter plane in the given time is $94.44 m$ .

Step by step solution

Average velocity, $v_{a v g} = 3400 km/h$

Time interval, ${∆t=100m/s=100×10}^{- 3} s$

The expression for the average velocity is given as follows:

$(v) = \frac{d i s \tan c e (∆ s)}{t i m e (∆ t)}$ $v_{a v g} = \frac{∆ x}{∆ t}$ … (i)

Here, $∆ x$ is the displacement and $∆ t$ is the time interval

Convert the velocity from km/h to m/s as:

$v = 3400 \frac{km}{h} \times \frac{1000 m}{km} \times \frac{1 h}{3600 s} = 944.44 m/s$

Using equation (i) the distance traveled can be calculated as follows:

$∆ x = v \times ∆ t = 944.44 {m/s×100×10}^{- 3} s = 94.44 m$

Thus, the distance travelled by the fighter plane in the given time is $94.44 m$ .

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