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Chapter 2: Q19P (page 33)

At a certain time, a particle had a speed of18m/sin positive x direction, and 2.4 slater, its speed was 30 m/s in the opposite direction. What is the average acceleration of particle during this 2.4 sinterval?

Short Answer

Expert verified

Average acceleration of particle during 2.4s is -20m/s2

Step by step solution

01

Given

vi=+18m/svf=-3.0m/s

t1=0s, (instance at which we started observing the particle) and

t2=2.4s

02

To understanding the concept

The problem deals with the average acceleration which refers to the rate at which the velocity changes. Average acceleration can be found using the formula for the average acceleration and given data.

Formula:

The average acceleration is given by,

aavg=∆V∆t

03

the average acceleration of particle during this 2.4 s interval

Using average acceleration equation we get,

aavg=∆V∆t=vft2-viti2.4-0=-20m/s2

Average acceleration calculated is-20m/s2 and the magnitude is 20m/s2.

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