Figure 2-44 gives the acceleration a versus time t for a particle moving along an x axis. The ‘a’ axis scale is set by as=12.0m/s2. Att=2.0s, the particle’s velocity is 7.0 m/s. What is its velocity att=6.0s?

Short Answer

Expert verified

The velocity of the particle at t=6.0sisrole="math" localid="1660885428340" 39m/s

Step by step solution

01

Given information

as=12.0m/s2t=-2.0sv0=7.0m/s

02

Kinematic Equations of Motion

Kinematics is the study of how a system of bodies moves without taking into accounts the forces or potential fields that influence the motion. The equations which are used in the study are known as kinematic equations of motion.

Formula:

The final velocity is given by

vf=v0+-26adt

03

Calculations for the velocity of the particle

The velocity of the particle at t=6.0seccan be calculated as,

vf=v0+-26adt

From thegiven graph the acceleration as a function of t can be written as,

a=2t

So,

vf=v0+-262tdtvf=7+2t22-26vf=7+32=39m/s

Hence, the velocity of the particle will be 39 m/s

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A rock is thrown vertically upward from ground level at time t=0 . Atrole="math" localid="1656149217888" t=1.5s ,it passes the top of a tall tower, and 1.0 s later, it reaches its maximum height. What is the height of the tower?

(a) If the position of a particle is given byx=20t-5t2, where x is in m and t in secwhen, if ever, the particle’s velocity is zero? (b) When is its acceleration a zero? (c) For what time range (positive or negative) is a negative? (d) Positive? (e) Graph x(t), v(t) and a(t).

When a high-speed passenger train travelling at 161 km/hrounds a bend, the engineer is shocked to see that a locomotive has improperly entered onto the track from a siding and is a distance D=676ahead (Fig.2-32). The locomotive is moving at 29 km/h. The engineer of the high speed train immediately applies the brakes. (a)What must be the magnitude of resulting constant deceleration if a collision is to be just avoided? (b)Assume that engineer is atx=0when, at t=0, he first spots the locomotive. Sketch x(t) curves for the locomotive and high speed train for the cases in which a collision is just avoided and is not quite avoided.

On a dry road, a car with good tires may be able to brake with a constant deceleration of 4.29m/s2 . (a)How long does such a car, initially travelling at 24.6 m/s, take to stop? (b)How far does it travel in this time? (c)Graph x vs t and v vs t for the deceleration.

The position of a particle moving along an x axis is given byx=12t2-2t3, where x in metres and t in sec. Determine (a) the position. (b) the velocity, and (c) the acceleration of the particle at t=3 s . (d) What is the maximum positive coordinate reached by the particle and (e) at what time is it reached? (f) What is the maximum positive velocity reached by the particle, and (g) at what time is it reached? (h) What is the acceleration of the particle at the instant the particle is not moving? (Other than t=0)? (i) Determine the average velocity of the particle between t=0 and t=3 s.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free