In Fig. 4-29, particle P is in uniform circular motion, centered on the origin of an xy coordinate system. (a) At what values of θis the vertical component ryof the position vector greatest in magnitude? (b) At what values of θis the vertical component vyof the particle’s velocity greatest in magnitude? (c) At what values of θis the vertical component ay
of the particle’s acceleration greatest in magnitude?

Short Answer

Expert verified
  1. θ=90°or270°
  1. θ=0°or180°
  2. θ=90°or270°

Step by step solution

01

Given information

Position vector ris directed at an angle θfrom center.

02

To understand the concept

This problem is based on concept on uniform circular motion. It is the motion of a body moving at a constant speed on a circular path.

Formulae:

Position vector can be written as:

r=rxi^+ryj^

Where,

rx=rcosθ

ry=rsinθ

03

(a) To find the values of at which the vertical component of the position vector greatest in magnitude?

Vertical component of position vector as:

ry=rsinθ

And it would be greatest when θ=90°or 270°, because sine function has max value at90°and70°

04

(b) To find the values of at which the vertical component of the particle’s velocity greatest in magnitude?

Vertical component of velocity:

vy=drydt=rcos(θ)

And it would be greatest when θ=0°or180°because cos function has max value atθ=0°and180° .

05

(c) To find the values of at which the vertical component of the particle’s acceleration greatest in magnitude?

Vertical component of particle’s acceleration:

ay=dvydt=-rsinθ

Sine function have max value at 90°and270°. Hence, acceleration would be max atθ=90°or270° .

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