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Chapter 4: Q21P (page 85)

A dart is thrown horizontally with an initial speed of10m/stoward pointP, the bull’s-eye on a dart board. It hits at pointQon the rim, vertically belowP,0.19s later. (a)What is the distancePQ? (b) How far away from the dart board is the dart released?

Short Answer

Expert verified

(a) Distance,PQis0.18m

(b) Distance of the released dart from the dart board is1.9m

Step by step solution

01

Given information

It is given that,


02

To understand the concept of free fall

Considering the concept of free fall and the fact that there is no acceleration in the horizontal direction, it is possible to find the distance by which dart moves down, given the time for the horizontal travel.This problem is based on kinematic equations that describe the motion of an object with constant acceleration. Here, the second kinematic equation can be used to find the distances.

Formula:

The displacement in kinematic equation can be written as,

(i)

03

to find the distance PQ

Vertical distance of the dart is givenby,

04

(b) to find the distance of the released dart from the dart board

It is given that,

Thus,

x=1.9m

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