The radionuclideIr196decays by emitting an electron. (a) Into which square in Fig. 42-6 is it transformed? (b) Do further decays then occur?

Short Answer

Expert verified

a) It is transformed into beige square in Fig.42-6.

b) Further decays do occur.

Step by step solution

01

Write given data

In Fig.42-6, the radioactive decay of nuclide Ir196by emitting an electron is given.

02

Determine the concept of decay  

In beta decay, a nuclide decays while emitting an electron with a neutrino particle. This implies that the proton number of the nuclide is added by 1 more proton.

03

a) Calculate the square of the transformed radionuclide

In the figure 42-6, observe that the radionuclideIr196 is present in the beige square that resembles it radioactive nature with the given half-life of 52s.

04

b) Determine whether it continues decaying

By emitting an electron, the radionuclideIr196 undergoes a beta decay process. That can be given as follows:

Ir196Pt197+e-1+v

The product of the decay process is a radionuclide Pt197, which also lies in the beige region with a half-life of 18.3h.

Hence, even after the decay process, the decay still occurs.

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