The strong neutron excess (defined as ) of high-mass nuclei is illustrated by noting that most high-mass nuclides could never fission into two stable nuclei without neutrons being left over. For example, consider the spontaneous fission of a nucleus into two stable daughter nuclei with atomic numbers and . From Appendix F, determine the name of the (a) first and (b) second daughter nucleus. From Fig. 42-5, approximately how many neutrons are in the (c) first and (d) second? (e) Approximately how many neutrons are left over?

Short Answer

Expert verified
  1. The name of the first daughter nucleus is yttriume .
  2. The name of the second daughter nucleus is iodine .
  3. There are 50 neutrons in the first daughter nucleus.
  4. There are 74 neutrons in the second daughter nucleus.
  5. There are 19 neutrons left over after the emission process.

Step by step solution

01

The given data:

Spontaneous emission of the nucleus into two daughter nuclei with atomic numbers 39 and 53 is given.

02

Understanding the concept of radioactive emission:

As per the problem, the spontaneous emission of the uranium substance into two daughter nuclei cannot be a stable emission process till there are neutrons left over after the decay process. Here, high mass nuclei undergo the process of fission to give two stable daughter nuclei and eject some amount of energy to follow the conservation of energy concept. This conservation law indicates that the internal forces of the nuclei involved in the process are balanced.

Formula:

The number of neutrons of a nucleus is,

N = A - Z ….. (i)

Here, is the atomic mass and Z is the atomic number.

03

(a) Calculation to identify the first daughter nucleus:

Using the given data and the periodic table (or Appendix F and/or Appendix G), you can see that the atomic number Z = 39 corresponds to the nucleus of the element .

Hence, the first daughter nucleus is yttrium .

04

(b) Calculation to identify the second daughter nucleus:

Using the given data and the periodic table (or Appendix F and/or Appendix G), you can see that the atomic number Z = 53 corresponds to the nucleus of the element .

Hence, the second daughter nucleus is iodine.

05

(c) Calculation of the number of neutrons of the first daughter nucleus:

As the molar mass of Yttrium is 88.905 , therefore there will be approximately nucleons in the nucleus of Yttrium. Therefore, the number in Yttrium nucleus is approximately,

89 - 39 = 50

A detailed listing of stable nuclides shows that the stable isotope of yttrium has neutrons (this can also be inferred from the Molar Mass values listed in Appendix F).

Hence, there are 50 neutrons in the first daughter nucleus.

06

(d) Calculation of the number of neutrons of the second daughter nucleus:

The molar mass of Iodine is 126.9044 g/mol . Therefore there will be approximately 127 nucleons in Iodine nucleus is approximately 127 - 53 = 74 .

A detailed listing of stable nuclides shows that the stable isotope of iodine has 74 neutrons (this can also be inferred from the Molar Mass values listed in Appendix F).

Hence, there are 74 neutrons in the first daughter nucleus.

07

(e) Calculation of the left over neutrons:

From the given data, the atomic mass of the uranium can be interfered as,

Au=235

Similarly, the atomic mass of yttrium is given using equation (i) and the above data as:

Ay=39+50=89

Similarly, the atomic mass of iodine is given using equation (i) and the above data as:

AI=53+74=127

Now, you are given that the fission process is not stable without some neutrons left over. Thus, the number of neutrons is calculated as follows:

n=235-89-127=19

Hence, the left-over neutrons number is 19 .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What is the binding energy per nucleon of 262Bh? The mass of the atom is 262.1231u.

Large radionuclides emit an alpha particle rather than other combinations of nucleons because the alpha particle has such a stable, tightly bound structure. To confirm this statement, calculate the disintegration energies for these hypothetical decay processes and discuss the meaning of your findings:

(a)U238Th232+He3(b)U235Th231+He4(c)U235Th230+He5

The needed atomic masses are

role="math" localid="1661928659878" Th232232.0381uHe33.0160uTh231231.0363uHe44.0026uTh230230.0331uHe55.0122uU235235.0429u

Two radioactive materials that alpha decay,U238and T232h, and one that beta decaysK40, are sufficiently abundant in granite to contribute significantly to the heating of Earth through the decay energy produced. The alpha-decay isotopes give rise to decay chains that stop when stable lead isotopes are formed. The isotopeK40has single beta decay. (Assume this is the only possible decay of that isotope.) Here is the information:

In the table Qis the totalenergy released in the decay of one parent nucleus to the finalstable endpoint and fis the abundance of the isotope in kilograms per kilogram of granite;means parts per million. (a) Show that these materials produce energy as heat at the rate of1.0×10-8Wfor each kilogram of granite. (b) Assuming that there is2.7×1022kgof granite in a 20-km-thick spherical shell at the surface of Earth, estimate the power of this decay process over all of Earth. Compare this power with the total solar power intercepted by Earth,1.7×1017W1.

A radiation detector records 8700 counts in 1.00 min. Assuming that the detector records all decays, what is the activity of the radiation source in (a) Becquerel and (b) curies?

From data presented in the first few paragraphs of Module 42-3, find (a) the disintegration constant λand (b) the half-life of 238U

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free