Figure 42-16 gives the activities of three radioactive samples versus time. Rank the samples according to their (a) half-life and (b) disintegration constant, greatest first. (Hint:For (a), use a straightedge on the graph.)

Short Answer

Expert verified
  1. The rank of the samples according to their half-life is C > B > A.
  2. The rank of the samples according to their disintegration constant is A > B > C.

Step by step solution

01

Given data

Figure 42-16 gives the activities of three radioactive samples versus time is given.

02

Understanding the concept of decay  

Half-life is the time required for a quantity to reduce to half of its initial value during the radioactive decay process.

The disintegration constant of a radioactive substance is defined as the ratio of its instantaneous rate of disintegration to the number of nuclides present at that time.

The half-life and disintegration constant of a nuclide are inversely proportional to each other.

Formulae:

The disintegration constant,λ=ln2Tv2............(1)

Where,Tv2is the half-life of the substance,

The rate of decay, R=λN........(2)

03

a) Calculation for the rank of the samples according to their half-lives

From the graph, we can see that the rate of.decay of the samples at half of their time decay is in the order of: A > B > C

Thus, from equations (1) and (2), we can see that the rate of decay is inversely proportional to their half-lives,R=ln@Tv2N.

Hence, the rank of the samples according to their half-lives is given by C > B > A.

04

b) Calculation of the rank of the samples according to their disintegration constants

Now, from part (a) calculations, the rank according to half-lives is given as: C > B > A

Thus, from equation (1), we see that disintegration constant is inversely proportional to the half-life.

Hence, the ranking of the samples according to disintegration constant is A > B > C.

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Most popular questions from this chapter

Question: At the end of World War II, Dutch authorities arrested Dutch artist Hans van Meegeren for treason because, during the war, he had sold a masterpiece painting to the Nazi Hermann Goering. The painting, Christ and His Disciples at Emmausby Dutch master Johannes Vermeer (1632–1675), had been discovered in 1937 by van Meegeren, after it had been lost for almost 300 years. Soon after the discovery, art experts proclaimed that Emmauswas possibly the best Vermeer ever seen. Selling such a Dutch national treasure to the enemy was unthinkable treason. However, shortly after being imprisoned, van Meegeren suddenly announced that he, not Vermeer, had painted Emmaus. He explained that he had carefully mimicked Vermeer's style, using a 300-year-old canvas and Vermeer’s choice of pigments; he had then signed Vermeer’s name to the work and baked the painting to give it an authentically old look.

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