In Fig. 15-64, a 2500 Kgdemolition ball swings from the end of a crane. The length of the swinging segment of cable is 17m. (a) Find the period of the swinging, assuming that the system can be treated as a simple pendulum. (b) Does the period depend on the ball’s mass?

Short Answer

Expert verified
  1. Period of swinging by assuming the system as a simple pendulum is .
  2. The period of a simple pendulum does not depend on the ball’s mass.

Step by step solution

01

The given data

  • Mass of the ball,(m)=2500kg.
  • Length of a cable,(L)=17m.
02

Understanding the concept of SHM

Using the formula of the period of the simple pendulum we can find the period of swinging, and hence, we can determine whether the period of the simple pendulum depends on the ball’s mass or not.

Formula:

The period of oscillation,

03

(a) Calculation of period 

From equation (i), we can find the period of oscillations of the ball as:

T=2π17M9.8M/S2=8.3S

Therefore, the period of swinging by assuming the system as a simple pendulum is 8.3S

04

(b) Checking whether the period of the ball depends on the ball’s mass or not

From equation (i) of the period of a body’s oscillation, it can be clearly seen that the term “period” only depends on the body’s length and acceleration.

From this relation, we can say that period is independent of the mass because this equation does not contain term .

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Most popular questions from this chapter

In Figure 15-37, two blocks(m=1.8kgandM=10kg)(and) and a spring (k=200 N/m) are arranged on a horizontal, frictionless surface. The coefficient of static friction between the two blocks is 0.40.What amplitude of simple harmonic motion of the spring–blocks system puts the smaller block on the verge of slipping over the larger block?

A block is on a horizontal surface (a shake table) that is moving back and forth horizontally with simple harmonic motion of frequency 2.0Hz. The coefficient of static friction between block and surface is0.50. How great can the amplitude of the SHM be if the block is not to slip along the surface?

When a 20 Ncan is hung from the bottom of a vertical spring, it causes the spring to stretch 20 cm .

  1. What is the spring constant?
  2. This spring is now placed horizontally on a frictionless table. One end of it is held fixed, and the other end is attached to a 5.0 Ncan. The can is then moved (stretching the spring) and released from rest. What is the period of the resulting oscillation?

A block sliding on a horizontal frictionless surface is attached to a horizontal spring with a spring constant of 600N/m. The block executes SHM about its equilibrium position with a period of0.40sand an amplitude of0.20m. As the block slides through its equilibrium position, a role="math" localid="1657256547962" 0.50kgputty wad is dropped vertically onto the block. If the putty wad sticks to the block, determine (a) the new period of the motion and (b) the new amplitude of the motion.

A simple harmonic oscillator consists of a block attached to a spring with k=200 N/m. The block slides on a frictionless surface, with an equilibrium point x=0and amplitude 0.20 m. A graph of the block’s velocity v as a function of time t is shown in Fig. 15-60. The horizontal scale is set byts=0.20s. What are (a) the period of the SHM, (b) the block’s mass, (c) its displacement att=0, (d) its acceleration att=0.10s, and (e) its maximum kinetic energy.

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