Question: A block rides on a piston that is moving vertically with simple harmonic motion.

  1. If the SHM has period 1.0 s, at what amplitude of motion will the block and piston separate?
  2. If the piston has amplitude of 5.0 cm, what is the maximum frequency for which the block and piston will be in contact continuously?

Short Answer

Expert verified

Answer:

  1. The amplitude of motion at which the block and piston will separate if SHM has a time period 1.0 s is 0.25 m
  2. The maximum frequency for which the block and piston will come in contact continuously if the piston has an amplitude of 5.0 cm is 2.2Hz

Step by step solution

01

The given data

  1. Period of motion, T = Is
  2. Amplitude of piston,xm= cm


02

Understanding the concept of simple harmonic motion

The piston and block will separate when the acceleration is maximum, and it is equal to gravitational acceleration. Therefore, using the relation between angular velocity and the period of SHM, we can find the amplitude of motion at which the block and piston will separate if SHM has a period. Also, we can find maximum frequency using the relation between angular velocity and frequency.

Formulae:

The angular frequency of a body in motion,(i)ω=2πT

The angular frequency of a body,ω=2πf(ii)

The acceleration of a body is directly proportional to displacement,am=ω2xm(iii)

03

a) Calculation of amplitude of motion

The general expression of position & acceleration of motion is given as:

x=xmcosωt+fa=xmω2cosωt+f

Piston and block separates when, am= g

So using equation (iii), we get the acceleration as:

xmω2=g......................................................(a)2πT2xm=g(from equation (ii))xm=gT24π2=9.8ms21.0s24π2=0.25m

Therefore, theamplitude of motion at which the block and piston will separate if the SHM has period 1.0 is 0.25.

04

b) Calculation of maximum frequency  

  1. Using equations (a) & (ii) and the given value of amplitude of piston,

xm2πf2=gxm4π2f2=gf2=gxm4π2f=12πgxm=12π9.80.05m=2.2Hz

Therefore, maximum frequency for which the block and piston will be in contact continuously if the piston has the amplitude of 5.0 cm is 0.997 Hz.

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Most popular questions from this chapter

An object undergoing simple harmonic motion takes 0.25 sto travel from one point of zero velocity to the next such point. The distance between those points is 36 cm.

(a) Calculate the period of the motion.

(b) Calculate the frequency of the motion.

(c) Calculate the amplitude of the motion.

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A simple harmonic oscillator consists of a 0.50 kgblock attached to a spring. The block slides back and forth along a straight line on a frictionless surface with equilibrium point x=0. At t=0the block is at x=0and moving in the positive x direction. A graph of the magnitude of the net forceFon the block as a function of its position is shown in Fig. 15-55. The vertical scale is set by FS=75.0N. What are (a) the amplitude and (b) the period of the motion, (c) the magnitude of the maximum acceleration, and (d) the maximum kinetic energy?

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