Find the mechanical energy of a block–spring system having a spring constant 1.3 N/ cmofand oscillation amplitude of 2.4cm.

Short Answer

Expert verified

The mechanical energy of the block-spring system is3.74×10-2J

Step by step solution

01

The given data

  1. The amplitude of motion,xm=2.4cmor0.024m
  2. The spring constant of the system,k=1.3N/cmor130N/m.
02

Understanding the concept of mechanical energy

We can find the mechanical energy of the block-spring system using the law of conservation of energy.

Formula:

The elastic P.E energy of the system PE=12kx2....(1)

The law of conservation of energy gives E= constant (2)

03

Calculation of mechanical energy of the spring-block system

From equation (ii), we can say that the mechanical energy of the system = the maximum elastic P.E energy of the system. Hence, we get the total energy of the system as:

E=12kxm2=12130(0.024)2 =3.74×10-2J

Therefore, the mechanical energy of the block-spring system is3.74×10-2J.

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