Figure shows the kinetic energy Kof a simple harmonic oscillator versus its position . The vertical axis scale is set by Ks=4.0J. What is the spring constant?

Short Answer

Expert verified

The spring constant of a simple harmonic oscillator is 8.33×102N/m.

Step by step solution

01

The given data

From graph, we can say that,

  1. Total energy of the system E = 6.0 J,
  2. The amplitude of the oscillation, Xm=12cmor0.12m.
02

Understanding the concept of motion

Using the given graph we can find the total energy and amplitude of motion, so we can find the spring constant.

Formula:

The energy of the system of the harmonic oscillator,

E=12kxm2...(1)

03

Calculation of spring constant

Using equation (i) and the given values, we get the spring constant as given:

6.012k(0.12)2k=8.33×102N/m

The value of the spring constant is8.33×102N/m .

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The physical pendulum in Fig. 15-62 has two possible pivot points A and B. Point A has a fixed position but B is adjustable along the length of the pendulum as indicated by the scaling. When suspended from A, the pendulum has a period ofT=1.80s. The pendulum is then suspended from B, which is moved until the pendulum again has that period. What is the distance L between A and B?

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