Question:The uncertainty in the position of an electron along an xaxis

is given as 50pm, which is about equal to the radius of a hydrogen

atom. What is the least uncertainty in any simultaneous measurement

of the momentum component of this electron?

Short Answer

Expert verified

The least uncertainty in the momentum component pxof this electron is

px=2.1×10-24kgms

Step by step solution

01

Identifying the data given in the question.

The uncertainty in the position of the electron is

x=50pm=50×10-12m

02

Concept used to solve the question

Heisenberg’s Uncertainty Principle

According to Heisenberg’s Uncertainty Principle, the uncertainty in position and momentum are related as,

xpxh2π

Where;

x is uncertainty in position along the axis.

pxis uncertainty in momentum along the axis.


his plank’s constant.

03

Finding the least uncertainty in the momentum component px

According to Heisenberg’s Uncertainty Principle

xpxh2π

The least uncertainty possible when

xpx=h2π

Therefore,

px=h2πx

Substituting the values,

px=6.634×10-34J.s2π50×10-12m=2.1×10-24kgms-1

Hence the least uncertainty in the momentum component pxof this electron is

px=2.1×10-24kgms-1

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