What is the maximum kinetic energy of electrons knocked out of a thin copper foil by Compton scattering of an incident beam of 17.5 keV x-rays? Assume the work function is negligible.

Short Answer

Expert verified

The maximum energy of electron is 1.1 keV.

Step by step solution

01

The given data

Compton scattering of an incident beam of 17.5 keV x-rays is done to knock electrons out a thin copper foil

02

Formula used

Here, Eλ=hc

Where E is energy

λis wavelength

h is Plank’s constant

C is speed of light.

03

Change in the wavelength

Using hc=1240 eVnm

Eλ=hcλ=hcEλ=1240 eVnm17500 eV=0.07086 nm

Maximum Crompton shift occur forφ=180° yields

Δλ=hcmec2(1cos180°)=1240 eVnm511×103 eV1(1)=0.00485 nm

04

New photon energy

New photon wavelengthλ' is

λ'=0.07086 nm+0.00485 nm=0.0757 nm

E'=hcλ'=1240 eVnm0.0757 nm=1.64×104 eV

New photon energy 16.4 keV

05

Kinetic energy of electron

Kinetic energy of electron is

E'E=17.5 keV16.4 keV =1.1 keV

Hence, maximum kinetic energy of electron is 1.1 keV

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