A 9.40 kgprojectile is fired vertically upward. Air drag decreases the mechanical energy of the projectile-Earth system by 68.0 kJduring the projectile’s ascent. How much higher would the projectile have gone were air drag negligible?

Short Answer

Expert verified

The height is h=738 m .

Step by step solution

01

Given data:

Mass of projectile, m = 9.40 kg

Decrease in mechanical energy, PE=68.0 kJ=68000 J

02

To understand the concept:

Potential energy is due to the position of the object from the earth’s surface.

Formula:

The potential energy is define by using following formula.

PE=mgh

Here, m is the mass, g is the acceleration due to gravity having a value 9.8m/s2, and h is the height.

03

Calculate the height:

Potential energy is given by,

PE=mgh68000J=9.40kg×9.8m/s2×hh=738m

Hence, 738 m much higher would the projectile have gone were air drag negligible.

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