A swimmer moves through the water at an average speed of 0.22 m/s. The average drag force is 110 N. What average power is required of the swimmer?

Short Answer

Expert verified

Average power required of the swimmer is 24 W .

Step by step solution

01

Given data:

An average speed of the swimmer through the water, v = 0.22 m/s

Average drag force on the swimmer, F = 110 N

02

To understand the concept:

Using the formula between power, force, and velocity, you can find an average power required of the swimmer.

Formula:

P = Fv

Here, P is the average power, F is the average drag force, and v is the average speed.

03

Calculate the average power required of the swimmer:

The average power required of the swimmer is,

P = Fv

Since the direction of the force and velocity is the same, Power is,

P=(110N)(0.22m/s)=24.2W24W

Hence, an average power required of the swimmer is 24 W .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A boy is initially seated on the top of a hemispherical ice mound of radius R = 13.8 m. He begins to slide down the ice, with a negligible initial speed (Figure). Approximate the ice as being frictionless. At what height does the boy lose contact with the ice?

The summit of Mount Everest is 8850 mabove sea level. (a) How much energy would a 90 kgclimber expand against the gravitational force on him in climbing to the summit from sea level? (b) How many candy bars, at 1.25 MJper bar, would supply an energy equivalent to this? Your answer should suggest that work done against the gravitational force is a very small part of the energy expended in climbing a mountain.

A 60 kg skier leaves the end of a ski-jump ramp with a velocity of 24 m/s directed 25°above the horizontal. Suppose that as a result of air drag the skier returns to the ground with a speed of 22 m/s, landing 14 m vertically below the end of the ramp. From the launch to the return to the ground, by how much is the mechanical energy of the skier-Earth system reduced because of air drag?

A 70.0 kgman jumping from a window lands in an elevated fire rescue net 11.0 mbelow the window. He momentarily stops when he has stretched the net by 1.50 m. Assuming that mechanical energy is conserved during this process and that the net functions like an ideal spring, find the elastic potential energy of the net when it is stretched by 1.50 m.

The arrangement shown in Fig. 8-24 is similar to that in Question 6. Here you pull downward on the rope that is attached to the cylinder, which fits tightly on the rod. Also, as the cylinder descends, it pulls on a block via a second rope, and the block slides over a lab table. Again consider the cylinder–rod–Earth system, similar to that shown in Fig. 8-23b. Your work on the system is 200J.The system does work of 60Jon the block. Within the system, the kinetic energy increases by 130Jand the gravitational potential energy decreases by 20 J. (a) Draw an “energy statement” for the system, as in Fig. 8-23c. (b) What is the change in the thermal energy within the system?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free