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Chapter 44: Q35P (page 1364)

If Hubble’s law can be extrapolated to very large distances, at what distance would the apparent recessional speed become equal to the speed of light ?

Short Answer

Expert verified

The distance at which the apparent recessional speed become equal to the speed of light is $1.4 \times 10^{10} ly$ .

Step by step solution

01

Explain Hubble’s law and determine the formula

Hubble’s law connects the recession speed $v$ of a galaxy and its distance $r$ from us, are directly proportional.

$v = H r$ …… (1)

Here, $H$ is the Hubble constant.

02

Find the distance

Consider the Hubble’s law from the Equation (1) and the speed of the light $c$ as follows:

$\begin{matrix} v = H r \\ = c \end{matrix}$ ...... (2)

Rewrite the equation (2) as follows and substitute the constant values of and .

$\begin{array}{l} r = \frac{c}{H} \\ r = \frac{3.0 \times 10^{8} \frac{m}{s}}{0.0218 \frac{m}{s} .ly} \\ r = 1.376 \times 10^{10} ly \\ r \approx 1.4 \times 10^{10} ly \end{array}$

Therefore,thedistance, at which the apparent recessional speed become equal to the speed of light is. $1.4 \times 10^{10} ly$

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Most popular questions from this chapter

Consider thedecay $Λ^{0} \to p + π^{-}$ withthe $Λ^{0}$ at rest. (a) Calculate the disintegration energy. What is the kinetic energy of (b) the proton and (c) the pion?

The quark makeups of the proton and neutron are $u u d$ and, $u d d$ respectively. What are the quark makeups of (a) the antiproton and (b) the antineutron?

There are baryons with spin .Their symbols and quantum numbers for charge and strangeness are as follows:

	q	S		q	S
$∆^{-}$	-1	0	$\sum_{}^{* 0}$	0	-1
$∆^{0}$	0	0	$\sum_{}^{* +}$	+1	-1
$∆^{+}$	+1	0	$\equiv^{* 0}$	-1	-2
$∆^{+ +}$	+2	0	$\equiv^{* 0}$	0	-2
$\sum_{}^{* -}$	-1	-1	$Ω^{-}$	-1	-3

Make a charge–strangeness plot for these baryons, using the sloping coordinate system of Fig. 44-3. Compare your plot with this figure.

Use the conservation laws and Tables 44-3 and 44-4 to identify particle $x$ in each of the following reactions, which proceed by means of the strong interaction: (a) $p + p \to p + Λ^{0} + x$ (b) $p + \bar{p} \to n + x$ (c). $π^{-} + p \to Ε^{0} + K^{0} + x$

Question: By examining strangeness, determine which of the following decays or reactions proceed via the strong interaction: (a) $K^{0} \to π^{+} + π^{-}$ (b) $Λ^{0} + p \to Σ^{+} + n$ (c) $Λ^{0} \to p + π^{-}$ (d) $K^{-} + p \to Λ^{0} + π^{0}$ .

See all solutions

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