A proton can not decay into a neutron and a neutrino. Which of the following conservation laws would be violated if it did:(a) energy, (b) angular momentum, (c) charge, (d) lepton number, (e) linear momentum, (f) baryon number?

Neutron emission by an atomic nucleus is one example of neutron decay. unbiased neutron decay Inside an atomic nucleus, a neutron undergoes beta decay. Grand unified theories indicate that baryon decay also involves neutron decay.

We have given that,a proton cannot decay into a neutron and a neutrino.

Here we have to consider that a proton can decay into a neutron and a neutrino.

Let the equation,

$p^{+}\to n+\gamma$

Where, n is a neutron and$\gamma$ is neutrino.

Since neutrino and neutron have no charge, the charge conservation law is not violated.

The mass of the proton is slightly more than the proton, so the law of conservation of energy will be violated as the proton is stationary.

Now, for angular momentum, Because Proton, Neutron, and a neutrino have spin$\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.$, the angular momentum conservation law is violated.

For the lepton number, the lepton number of Proton and Neutron is zero, lepton number of Neutrino is one.

So, the lepton number conservation law is violated.

Since the proton is at rest, its momentum will be conserved during decay.

For the Baryon number, the baryon number of Proton and Neutron is one, and the Baryon number of Neutrino is zero.

So, the lepton number conservation law is conserved.

Hence, the charge conservation law, law of conservation of energy, angular momentum conservation law, and lepton number conservation law is violated.