An experimenter arranges to trigger two flashbulbs simultaneously, producing a big flash located at the origin of his reference frame and a small flash at 3.0km. An observer moving at a speed of 0.250cin the positive direction of xalso views the flashes. (a) What is the time interval between them according to her? (b) Which flash does she say occurs first?

Short Answer

Expert verified
  1. The time interval between the flashes is2.58×10-5s .
  2. The small flash occurs first in frame S'.

Step by step solution

01

The time dilation equation

The time dilation equation states that t'=t-βxc1-β2, where t-βxcshows that time measured in the reference frame of inertial observer.

02

The time interval between the flashes 

Lettsbe the time coordinate and xsbe the position coordinate of small flash. So, the time in the frameS'can be obtained using the formula t's=ts-βxsc1-β2.

Lettbbe time coordinate of big flash and xbbe the position coordinate of the big flash. So, the time of the big flash in the frameS'can be obtained using the formula .

t'b=t-βxbc1-β2

The time interval between the flashes can be obtained as follows:

t=t'b-t's=tb-βxbc1-β2-ts-βxsc1-β2=11-β2tb-βxbc-ts+βxsc

In frame , both the flashes occurs simultaneously. So, tb=ts. Then the above equation becomes:

t'=11-β2-βxbc+βxsc=βc1-β2xs-xb=0.2503×1081-0.250230000=2.58×10-5s

Thus, the time interval between both flashes is2.58×10-5s .

03

Occurrence of flashes

Here, from the calculation is it is clear that t'is positive, this means t'bis greater than t's. This implies the small flash occurs first.

Thus, the small flash occurs first in the frameS' .

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