In the reaction p+F19α+O16, the masses are m(p) = 1.007825 u, m(a) = 4.002603 u, m(F) = 18.998405 u, m(O) = 15.994915 u. Calculate the Q of the reaction from these data.

Short Answer

Expert verified

The Q value of the reaction is 8.12 MeV.

Step by step solution

01

Identification of given data

The mass of Fluorine nuclei is mF=18.998405u

The mass of Oxygen nuclei is mO=15.994915u

The mass of proton is mp=1.007825u

The mass of alpha particle is mα=4.002603u

The Q value of the reaction is the energy released due to the mass defect from reactant and products in reaction.

02

Determination of Q value of the reaction

The Q value of the reaction is given as:

Q=mp+mF-mα+mOc2

Here, c is the speed of light and its value in terms of mass and energy is 931.5 MeV/u

Substitute all the values in the above equation.

E=1.007825u+18.998405u-4.002603u+15.994915u931.5MeVuE=8.12MeV

Therefore, the Q value of the reaction is 8.12 MeV.

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